How to write 7+2-3-8 in sigma notation

Given f(x) = 3x + 4. Find F-1(7)<br><br> Please help I’ll give you brainiest answer 100points!!!!!

Musya8 [376]

Answer:

f⁻¹(7) = 1

Step-by-step explanation:

Step 1: Write out function

f(x) = 3x + 4

Step 2: Find f⁻¹(x) (or known as inverse f(x))

y = 3x + 4

x = 3y + 4

-3y + x = 4

-3y = 4 - x

y = -4/3 + x/3

Step 3: Plug in 7 into inverse f(x)

f⁻¹(7) = 7/3 - 4/3

f⁻¹(7) = 3/3

f⁻¹(7) = 1

6 0

3 years ago

Let P be a predicate. Determine whether or not each of the following implications is true and give a brief English explanation f

den301095 [7]

Answer:

See answer below

Step-by-step explanation:

1), Probably, your implication is ∀x∃yP(x,y)⇒∃x∀yP(x,y).

This implication is false. Consider the predicate P(x,y):="x<y" for real numbers x,y. Then, ∀x∃yP(x,y) is true: for all real x, there exists some y greater than x (take y=x+1 for example). However, ∃x∀yP(x,y) is false, as it would imply that there exists some real number x such that x is smaller than all real numbers, which is not true (real numbers do not have a minimum or a lower bound).

A short explanation would be, even if for all elements you can find one that makes a predicate true, you can not find one element that makes the predicate true for all elements.

2) Again, I assume that the predicate is ∃x∀yP(x,y)⇒∀x∃yP(x,y)

This implication is false. Consider the predicate P(x,y):="x is integer and xy=0 " for real numbers x,y. Then ∃x∀yP(x,y) is true, we need to take x=0. However, ∀x∃yP(x,y) is false, if you take x=1/2, 1/2 will never be an integer, no matter the value of y.

A short explanation would be, even if you can find one element that makes a predicate true for all elements, you can not always take an arbitrary element and find some element that makes the predicate true.

6 0

3 years ago

The bids in an online auction are represented by the arithmetic sequence shown below. Write an explicit formula to represent the

zmey [24]

(a) The nth term of the sequence is given by A(n)=195 + (n - 1)10.

(b) The 12th term of the sequence is A(12) = 305.

<h3>What is an arithmetic sequence?</h3>

One arithmetic progression with a common difference of 2 is the sequence 5, 7, 9, 11, 13, 15,...

The term "finite arithmetic progression" or "arithmetic progression" refers to a limited segment of an arithmetic progression.

A mathematical sequence has the following structure: a, a+d, a+2d, a+3d, etc., up to n terms. The initial term is a, the shared distinction is d, and n is the total number of words. Find the AP, the first term, the number of terms, and the common difference for the computation using the arithmetic sequence formulae. To determine the nth term, sum, or common difference of a given arithmetic sequence, many formulae related to arithmetic series are utilized.

A(n)=195+(n-1)10

The given arithmetic sequence is 195, 205, 215, 225,.....

The first term a =195

The common difference d= 205-195

d =215-205

d =225-215

So, d = 10

(a) The nth term is given by

A(n)=a+(n-1)d

A(n)=195+(n-1)10

(b) For n=12, the 12th term is given by

A(12)=195+11(10)

A(12)=305

Therefore, A(n)=195+(n-1)10

And A(12)=305

To know more about the arithmetic sequences, visit:

brainly.com/question/15412619

#SPJ1

8 0

1 year ago

22÷34=? what is answer <br>

kaheart [24]

Answer:

0.64705882352

when u round it, it will be

0.65

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Step-by-step explanation:

8 0

2 years ago

A server sees 90 customers over 6 hours. At the same rate, how many customers would the server see in 10 hours? *

nirvana33 [79]

Answer:

150

Step-by-step explanation:

First we have to find the unit rate. So we divide 90 by 6 and we get 15. So the server would see 15 customers in one hour. Now we multiply 15 by 10 and get 150.

If we want to check our answer we can multiply 6 by 15 and we get 90. So now we can conclude that both are true.

Hope I helped!!

6 0

3 years ago