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Solnce55 [7]
3 years ago
9

Math functions. Find the common difference from this sequence. Starts with t(1). 0,4,16,36,64

Mathematics
1 answer:
yuradex [85]3 years ago
6 0
The difference is that each number that comes after gets multiplied by 4

Hope I helped
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That means he had 400 or 4000mm
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Find the difference. 8x-(12x^2+5x)=
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Answer:

− 24 x − 12 h +3

Step-by-step explanation:

8x-(12x^2+5x)

<em>difference</em>

<u>f ( x + h )   and   f ( x ) , and plug these values into the difference quotient formula</u>

− 24 x − 12 h +3

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Robert was using a bucket that holds 243.5 ounces (oz) of water when full. The bucket loses 0.3 oz of water per second. After 20
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Answer:

237.5

Step-by-step explanation:

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So 237.5 is your answer  

4 0
3 years ago
Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g
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\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;% left side templates&#10;\begin{array}{llll}&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}\\\\&#10;--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\&#10;\left. \qquad   \right.  \textit{reflection over the x-axis}&#10;\\\\&#10;\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\&#10;\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see    \bf f(x)=\sqrt{x}\qquad &#10;\begin{array}{llll}&#10;g(x)=&\sqrt{0.5x}\\&#10;&\quad \uparrow \\&#10;&\quad  B&#10;\end{array}

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.
8 0
3 years ago
Read 2 more answers
Simplify the expression. write the answer using scientific notation 4(6.2x10^11)
Veseljchak [2.6K]
Answer:
= 2.48 × 10¹²
(scientific notation)

= 2.48e12
(scientific e notation)

= 2.48 × 10¹²
(engineering notation)
(trillion; prefix tera- (T))

= 2480000000000
<span>(real number)</span>
7 0
3 years ago
Read 2 more answers
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