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Mazyrski [523]
3 years ago
5

Give the coordinates of a point that would form a right triangle with the points given. Tell what you know about one of the coor

dinates of your new point
Mathematics
1 answer:
REY [17]3 years ago
7 0

Answer: (5,8)   SMASH THAT LIKE BUTTON

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Solve for R.<br> K=ar/p<br> Answer choices:<br> R=ka/p<br> R=kap <br> R=kp/a<br> R=a/kp
Dafna11 [192]
Multiply each side by p, so
kp = ar
Divide each side by a, so
kp/a = r
The answer is the third option
3 0
4 years ago
Read 2 more answers
Someone please help me with this
alexgriva [62]

Answer:

Value of x: 72, first option

Step-by-step explanation:

The sum of angles in a triangle is 180 degrees. In order to find x, one of the angles, add the other two angle measures subtracted from the sum of angles (180) as such:

180 - (51 + 57) =

180 - 108 =

x - 72 degrees

5 0
3 years ago
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Why do we use circles in constructions?
Licemer1 [7]
We use them to show if postulated and theorems are correct
7 0
3 years ago
9. In a rhombus whose side measures 34 and the smaller angle is 42°. Find the length of the larger diagonal, to the nearest tent
Veseljchak [2.6K]

Answer:

63.5

Step-by-step explanation:

The diagonals of a rhombus bisect opposite angles.

The longer diagonal bisects the 42° angle

The larger angle of the rhombus is 180 - 42 = 138

Let x = the length of the longer diagonal

You know two sides and the included angle of a triangle.

Using the law of cosines we get

x^{2} = 34^{2} + 34^{2} -2(34)(34) cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.150837...\\x = \sqrt{4030.150837} = 63.48x^{2} = 34^{2} + 34^{2} -2(34)(34)cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.1508...\\     x = \sqrt{4030.1508} \\          =  63.48x^2 = 34^2 + 34^2 - 2(34)(34) cos 138

      = 1156 + 1156 - 2312 c0s 138

      = 4030.1508...

x = sq rt 4030.1508...

  =  63.5

7 0
3 years ago
If x-1/x=5, find the value of x^3-1/x^3
Alexxx [7]
65 is the answer. Solve the first equation and then plug in.

7 0
3 years ago
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