Question

How many grams of sodium hyrdioxde are in 251.0ml f 0.600m

Answer 1

Answer:

There are 6.024 grams of sodium hydroxide in the solution.

Explanation:

$Molarity=\frac{Moles}{Volume (L)}$

$Moles (n)=Molarity(M)\times Volume (L)$

Moles of sodium hydroxide = n

Volume of sodium hydroxide solution = 251.0 mL = 0.251 L

Molarity of the sodium hydroxide = 0.600 M

$n=0.600 M\times 0.251 L=0.1506 mol$

Mass of 0.1506 moles of NaOH :

$40 g/mol\times 0.1506 mol = 6.024 g$

There are 6.024 grams of sodium hydroxide in the solution.