Explanation:
Answer
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The rule used here is that the algebraic sum of the oxidation numbers of all the atoms a molecule is zero.
Al2O32× ( oxidation number of Al)+3× ( Oxidation number of O ) = 0
2× ( Oxidation number of Al) +3(−2)=0
2× ( oxidation number of Al) +6
∴ Oxidation number of Al =+3
Answer:
Option (B) 6270J
Explanation:
The following were obtained from the question:
M = 100g
T1 = 30°C
T2 = 45°C
ΔT = 45 —30 = 15°C
C = 4.18J/g°C
Q=?
Q = MCΔT
Q = 100 x 4.18 x 15
Q = 6270J
Therefore, the total amount of heat absorbed is 6270J
Is this chemistry or something else?
40% solution of glucose is where the solution contains, by weight, 40% glucose and 60% water.
Therefore, if the total weight of the solution is 250 g,
mass of the glucose (C6H12O6) = 250 g * 40% = 100 g
mass of water (H2O) = 250 g * 60% = 150 g
Mass of water can also be calculated by subtracting the weight of glucose from the total weight of the solution:
mass of water = 250g-100g = 150g.
