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Hatshy [7]
3 years ago
5

How do the circulatory, respiratory, or digestive systems work together?

Chemistry
1 answer:
Alexandra [31]3 years ago
7 0

Answer:

by pumping blood throughout the body.

Explanation:

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It is primarily used as energy storage found in the cell membrane​
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Answer:

ATP—Adenosine triphosphate, a nucleotide which is the most important short-term energy storage compound in cells. It is the “energy currency” of the cell, necessary for practically all metabolic activities. Carbohydrate—A type of organic molecule made of carbon, hydrogen, and oxygen.

4 0
2 years ago
True or False: It is OK to use wet glassware for the aspirin synthesis without potentially affecting your yield
vesna_86 [32]

Answer:

False

Explanation:

Laboratory synthesis of aspirin is done by the acetylation of salicylic acid with the help of acetic anhydride .

As , the  acid anhydride is very sensitive to moisture , as it can hydrolyze into two molecules of  acids,

Hence , the reaction involving acid anhydride  are conducted in anhydrous solvents .

Hence ,

if water is  present in the glassware then , some of the acetic anhydride is wasted , Which in turns reduces the yield than that expected .

5 0
3 years ago
Which of the following statements concerning coordinate covalent bonds is correct? Group of answer choices One of the atoms invo
lys-0071 [83]
One of the atoms involved must be a metal and the other a nonmetal
6 0
3 years ago
A certain reaction has an activation energy of 66.41 kJ/mol. At what Kelvin temperature will the reaction proceed 3.00 times fas
swat32

Answer : The temperature will be, 392.462 K

Explanation :

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at T_1  = K_1

K_2 = rate constant at T_2 = 3K_1

Ea = activation energy for the reaction = 66.41 kJ/mole = 66410 J/mole

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 293 K

T_2 = final temperature = ?

Now put all the given values in this formula, we get:

\log (\frac{3K_1}{K_1})=\frac{66410J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{293K}-\frac{1}{T_2}]

T_2=392.462K

Therefore, the temperature will be, 392.462 K

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3 years ago
Radiaciones de ionización directa y de ionización indirecta.
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Answer:

ola what do u need to do?

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