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4vir4ik [10]
3 years ago
12

A woman standing on the ground sees a rocket ship move past her at 95% the speed of light. Compared to the rocket at rest, the w

oman sees the rocket's length as a. longer b. the same c. shorter
Physics
1 answer:
Rufina [12.5K]3 years ago
8 0

As per Einstein's theory of relativity we know that when an object will move with the speed comparable to the speed of light then the length of the object will be different from its length at rest position

This is also known as length contraction theory

As we know here that

L = L_0\sqrt{1 - \frac{v^2}{c^2}}

so here we know that

v = 0.95 c

so from above equation we will have

L = L_0\sqrt{1 - 0.95^2}

L = 0.31 L_0

so here the length will be SHORTER

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The reaction of H2 with F2 produces HF with ΔH = –269 kJ/mol of HF. If the H–H and H–F bond energies are 432 and 565 kJ/mol, res
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Answer:

The bond energy of F–F = 429 kJ/mol

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The bond energy of H–H = 432 kJ/mol

The bond energy of H–F = 565 kJ/mol

The bond energy of F–F = ?

Given that the standard enthalpy of the reaction:

<u>H₂ (g) + F₂ (g) ⇒ 2HF (g)</u>

ΔH = –269 kJ/mol

So,

<u>ΔH = Bond energy of reactants - Bond energy of products.</u>

<u>–269 kJ/mol = [1. (H–H) + 1. (F–F)]  - [2. (H–F)]</u>

Applying the values as:

–269 kJ/mol = [1. (432 kJ/mol) + 1. (F–F)]  - [2. (565 kJ/mol)]

Solving for , The bond energy of F–F , we get:

<u>The bond energy of F–F = 429 kJ/mol</u>

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4 years ago
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Answer:

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