B. The sound of the engine will get louder and the pitch higher.
Answer:
0.68 m
Explanation:
We know that the speed of sound in air is a product of frequency and wavelength. Taking speed of sound in air as 340 m/s
V=frequency*wavelength
Then wavelength is given by 350/500=0.68 m
Therefore, to repeat constructive interference at the listener's ear, a distance of 0.68 m is needed
3.8=7.446e+7
Hope this helped
Pl ease give brainliest
Answer:
θ = 45º
Explanation:
To find the solution, let's use the projectile launch equation
R = vo² sin 2θ / g
Where vo is the initial speed of the dolphin, T is the angle of the jump and g the gravity acceleration.
To obtain a maximum range, the sine T function must be 1,
sin 2θ = 1
2θ = sin⁻¹ 1
2θ = 90
θ = 45º
Therefore, the dolphin should jump at an angle of 45º from the horizontal
Answer:
9 ft*lb
Explanation:
super simple but you just have to understand that the integral is going with the curve
work = integral a to b of f(x)dx = integral 0 to 9 of 10/(1+x)^2dx = 9ft*lb