Answer:
The null and alternative hypotheses are:
Under the null hypothesis, the test statistic is:
Now, we have to find the right tailed z critical value at 0.10 significance level. Using the standard normal table, we have:
Since the test statistic is greater than the z critical value, we therefore, reject the null hypothesis and conclude that there is sufficient evidence to support the claim that the university students weigh more than the population.
Not sure why they put the x bit
ok so know this:
AGE=HGB=CHG=FHD
and
AGH=EGB=CHF=GHD
and
AGE+AGH=180
11.
AGE=FHD=30
12.
AGH=CHF=150
13.
CHF=BGE=110
14.
CHG+HGA=180
CHG+120=180
CHG=60
15.
BHG=3x=AGE=CHG=FHD
not sure, but if we did use the fact that BGH+DHG=180 and BGH=3x and DHG=2x+50 then BHG=78 degrees
16.
GHD=2x+50=CHF=EGB=AGH, if we use facts above then GHD=102 degrees
Dana would need 75 pickets of each color to have an equal amount.
75x4=300
She would need 43 more red pickets to equal 75. (32+43=75)
49 more green pickets to equal 75 (26+49=75)
66 more yellow pickets to equal 75 (9+66=75)
75 blue pickets to equal 75. (0+75=75)
La respuesta es trescientos setenta
you need to get a common denominator and subtract 20/32 from 26/32
z would equal 6
