By conservation of linear amount of movement we have:
m1v1i + m2v2i = m1v1f + m2v2f
Where,
v1i = v2i = 0 (assuming initial rest)
m1v1f + m2v2f = 0
Substituting the values:
m1 (-3) + (1) (150) = 0
Clearing m1:
m1 = (- (1) * (150)) / (- 3)
m1 = 50 Kg
answer:
his mass is 50 Kg
9x - y = 15
2x + 8y = 28
Use the substitution method.
Solve for y in the first equation.
9x - y = 15
-y = 15 - 9x
y = -15 + 9x
Now plug in y into the second equation.
2x + 8(-15 + 9x) = 28
2x - 120 + 72x = 28
74x - 120 = 28
74x = 148
x = 2
Plug x back into the rewritten first equation.
y = -15 + 9(2)
y = -15 + 18
y = 3
x = 2, y = 3
75 +10n = 15n
75 = 5n
15 = n
Therefore 15 classes
Answer:
$662.29
Step-by-step explanation:
