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Alex73 [517]
3 years ago
11

Whats the answer to this equation 3g+5=17

Mathematics
2 answers:
crimeas [40]3 years ago
7 0
3g + 5 = 17

thus, 3g = 17 - 5 = 12

thus, 3g = 12

thus, g = 12/3 = 4.

Thus, g = 4.
Papessa [141]3 years ago
4 0
3g+5=17 \ \ |-5\\ \\3g+5-5=17-5\\ \\3g=12 \ \ /:3 \\ \\g=\frac{12}{3}\\ \\ g=4


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Find the total surface area of this cone
fenix001 [56]

Answer:

S.A. = 1,017.36

Step-by-step explanation:

S.A. = \pi r^{2} + \pi rl

12 x 12 x 3.14 = 452.16

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What is f(2)>0 telling me about a graph?
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3 years ago
How do I solve 2m + n = 2 and 3m - 2n = 3 using substitution?
Leona [35]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • Solve 2m + n = 2 and 3m - 2n = 3 using substitution.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

We can use the substitution method to solve linear equations of this form. Let's solve for m & n.

\left. \begin{array}  { l  }  { 2 m + n = 2 } \\ { 3 m - 2 n = 3 } \end{array} \right.

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

2m+n=2, \: 3m-2n=3

Choose one of the equations and solve it for m by isolating m on the left-hand side of the equal sign.

2m+n=2

Subtract n from both sides of the equation.

2m=-n+2

Divide both sides by 2.

m=\frac{1}{2}\left(-n+2\right)  \\

Multiply 1/2 times -n+2.

m=-\frac{1}{2}n+1  \\

Substitute -\frac{n}{2}+1\\ for m in the other equation, 3m-2n=3.

3\left(-\frac{1}{2}n+1\right)-2n=3  \\

Multiply 3 times -\frac{n}{2}+1\\.

-\frac{3}{2}n+3-2n=3  \\

Add -\frac{3n}{2}\\ to -2n.

-\frac{7}{2}n+3=3  \\

Subtract 3 from both sides of the equation.

-\frac{7}{2}n=0  \\

Divide both sides of the equation by -\frac{7}{2}\\, which is the same as multiplying both sides by the reciprocal of the fraction.

\large \underline{\underline{ \bf \: n=0 }}

Substitute 0 for n in m=-\frac{1}{2}n+1\\. Because the resulting equation contains only one variable, you can solve for m directly.

\large \underline{ \underline{\bf \: m=1 }}

The system is now solved.

\huge \boxed{ \boxed{ \bf \: m=1, \: n=0 }}

4 0
3 years ago
Is my answer correct and how do you know? I just graphed it , is there another way I could do it?
Evgesh-ka [11]
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7 0
3 years ago
Read 2 more answers
Excursion boat on the river takes 2 1/2 hours to make the trip to a point 12 miles upstream and to return if the rate at which t
Mama L [17]

Answer:

Let the current speed be "c";

Then the boat speed in still wate is "5c":

-----------------------

Upstream speed:

distance = 12 miles ; rate = 5c-c = 4c mph ; time = 12/4c = 3/c hrs

---------------------------

Downstream speed:

distance = 12 miles ; rate = 5c+c = 6c mph ; time = 12/6c = 2/c hrs

Step-by-step explanation:

Equation:

time + time = 2 1/2 hrs

3/c + 2/c = 5/2

Multiply thru by 2c to get:

6 + 4 = 5c

c = 2 mph (speed of the current)

5c = 10 mph (speed of the boat in still water)

3 0
2 years ago
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