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mel-nik [20]
3 years ago
6

Develop a crawler that collects the email addresses in the visited web pages. You can write a function emails() that takes a doc

ument (as a string) as input and returns the set of email addresses (i.e., strings) appearing in it. You should use a regular expression to find the email addresses in the document.
Computers and Technology
1 answer:
Mars2501 [29]3 years ago
5 0

Answer:

see explaination

Explanation:

import re

def emails(document):

"""

function to find email in given doc using regex

:param document:

:return: set of emails

"""

# regex for matching emails

pattern = r'[\w\.-]+at[\w\.-]+\.\w+'

# finding all emails

emails_in_doc = re.findall(pattern, document)

# returning set of emails

return set(emails_in_doc)

# Testing the above function

print(emails('random text ertatxyz.com yu\npopatxyz.com random another'))

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A function defined beginning with void SetNegativesToZeros(int userValues[], ... should modify userValues such that any negative
Stels [109]

Answer:

   public static void setNegativesToZero(int userValues[]){

       System.out.println("Array before setting negatives to zero "+Arrays.toString(userValues));

       for(int i=0; i<userValues.length; i++){

           if(userValues[i]< 1){

               userValues[i] = 0;

           }

       }

       System.out.println();

       System.out.println("Array After setting negatives to zero "+Arrays.toString(userValues));

   }

Explanation:

Using Java programming Language, the method is created to receive an array of ints as parameter (as specified in the question)

Using a for loop, we iterate over the entire array checking for values that are negative (<0) and setting them to zero.

See a complete program below

import java.util.Arrays;

import java.util.Scanner;

public class num1 {

   public static void main(String[] args) {

   // Create an array and assign values

       int [] arr = {1,2,3,-1,1,2,-4};

   //Calling the method setNegativesToZero

   setNegativesToZero(arr);

   }

//Creating the Method

   public static void setNegativesToZero(int userValues[]){

       System.out.println("Array before setting negatives to zero "+Arrays.toString(userValues));

       for(int i=0; i<userValues.length; i++){

           if(userValues[i]< 1){

               userValues[i] = 0;

           }

       }

       System.out.println();

       System.out.println("Array After setting negatives to zero "+Arrays.toString(userValues));

   }

}

3 0
3 years ago
Instructions The population of town A is less than the population of town B. However, the population of town A is growing faster
weeeeeb [17]

Answer: The c++ program is given below.

#include <iostream>

using namespace std;

int main() {

float townA, townB, growthA, growthB, populationA, populationB;

    int year=0;    

cout<<"Enter present population of town A : ";

cin >> townA;  

cout<<endl<<"Enter present growth rate of town A : ";

cin >> growthA;

growthA = growthA/100;  

cout<<endl<<"Enter present population of town B : ";

cin >> townB;  

cout<<endl<<"Enter present growth rate of town B : ";

cin >> growthB;

growthB = growthB/100;  

do

{

    populationA = townA + (townA * growthA);

    populationB = townB + (townB * growthB);      

    townA = populationA;

    townB = populationB;      

    year++;      

}while(populationA < populationB);  

cout<<endl<<"After " <<year<< " years, population of town A is "<<populationA << " and population of town B is "<< population<<endl;

return 0;

}

Explanation:

All the variables for population and growth rate are declared with float datatype.

The user inputs the present population of both the towns.

The growth rate entered by the user is the percentage growth.

For example, town A has 10% growth rate as shown in the output image.

The program converts 10% into float as 10/100.

growthA = growthA/100;

growthB = growthB/100;

The above conversion is done to ease the calculations.

The year variable is declared as integer and initialized to 0.

The growth in population is computed in a do-while loop. After each growth is calculated, the year variable is incremented by 1.

The loop continues until population of town A becomes greater than or equal to population of town B as mentioned in the question.

Once the loop discontinues, the final populations of town A and town B and the years needed for this growth is displayed.

The new line is introduced using endl keyword.

The function main has return type int hence, 0 is returned at the end of the program.

6 0
4 years ago
When typing in a cell, hitting Tab will bring which result?
alexandr402 [8]

it's B I took the test :)

8 0
3 years ago
Read 2 more answers
The typing area is bordered on the right side by bars in ms word
lidiya [134]

Answer:

Explanation:

PTA NHI

6 0
3 years ago
5x + 2y = 3<br>2x + 3y = 13​
satela [25.4K]

5x+2y=3

Slope = -5.000/2.000 = -2.500

x-intercept = 3/5 = 0.60000

y-intercept = 3/2 = 1.50000

2x+3y=13

Slope = -1.333/2.000 = -0.667

x-intercept = 13/2 = 6.50000

y-intercept = 13/3 = 4.33333

5 0
3 years ago
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