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hjlf
3 years ago
9

Please help me with this! show that {1,2} ⊆ {x|x^4 - x^3 - x^2 - 5x + 6 = 0}

Mathematics
1 answer:
Llana [10]3 years ago
6 0

The set \{x\mid x^4-x^3-x^2-6x+6=0\} is the set of all values of x that are solutions to the given equation. So all you need to do is check whether x=1 and x=2 satisfy the equation.

x=1\implies 1^4-1^3-1^2-5+6=0

x=2\implies2^4-2^3-2^2-10+6=0

The equation holds, so both 1 and 2 are solutions, and hence \{1,2\} is a subset of the solutions.

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Answer:

18 minutes

Step-by-step explanation:

A = A₀ (½)^(t / T)

where A is the final amount,

A₀ is the initial amount,

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A = 140 when t = 10.  Solve for the half life:

140 = 700 (½)^(10 / T)

0.2 = ½^(10 / T)

log 0.2 = (10 / T) log 0.5

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When A = 40, t is:

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3 years ago
The University of Montana ski team has thirteen entrants in a men's downhill ski event. The coach would like the first, second,
sleet_krkn [62]

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