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Elena L [17]
3 years ago
13

Please help me on how to solve this, I am confused thank you. verify sin(180 °-θ)=sinθ

Mathematics
1 answer:
RideAnS [48]3 years ago
3 0

Answer:

Step-by-step explanation:

sin(a-b)=sina cos b-cos a sin b

sin 180°=0

cos 180°=-1

sin(180-\theta)=sin 180 cos \theta-cos 180sin \theta \\=0* cos \theta-(-1)  sin \theta\\=sin \theta

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→ (2√5 + 3√2)² = (2√5)² + (3√2)² + 2(2√5)(3√2)

We are aware about the fact that root means 1/2 and square of root means 2/2 that is 1. Using this we get:

→ (2√5 + 3√2)² = 4(5) + 9(2) + 2(2√5)(3√2)

Solve the brackets, to do so first put the like terms in one box.

→ (2√5 + 3√2)² = 4(5) + 9(2) + 2(2*3)(√5)(√2)

Solve the rest calculations.

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Option (a) (38 + 12√10) is the correct option.

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