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Lerok [7]
3 years ago
6

Divide. 8 2/5÷(−2 1/5) Enter your answer as a mixed number, in simplified form, in the box.

Mathematics
1 answer:
Reptile [31]3 years ago
6 0

Answer:

-3 \frac{9}{11}

Step-by-step explanation:


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Suppose that 10 sophomores, 3 juniors, and 10 seniors are candidates for a prestigious mathematics award of which three will be
faltersainse [42]

Answer:

1771 possible ways

Step-by-step explanation:

In this case, we need to know first how many candidates are in total:

10 + 3 + 10 = 23 candidates in total.

Now, we need to choose 3 of them to receive an award. In this case, we have several scenarios, but as it's an award we can also assume that the order in which the candidates are chosen do not matter, so, the formula to use is the following:

C = m! / n! (m - n)!

Where m is the total candidates and n, is the number of candidates to be chosen. Replacing this data we have:

C = 23! / 3! (23 - 3)!

C = 2.59x10^22 / 6(2.43x10^18)

C = 1771

So we have 1771 ways of choose the candidates.

7 0
3 years ago
In a + b, if b is divisible by n, is a + b divisible by n?
levacccp [35]

Answer:

Step-by-step explanation:

I think the answer should be no because only b is divisible by n not a

3 0
3 years ago
What do the factors (x+2)(-8x+70)in the factored form represent?
Tasya [4]

Answer:

-2(x+2)(4x-35)

Step-by-step explanation:

5 0
3 years ago
Which of the following trigonometric inequalities has no solution over the interval 0 ≤ x ≤ 2pi radians?
valentinak56 [21]

Answer:

A .cos(x)<1

Step-by-step explanation:

According to the first inequality

cos(x)<1

x < arccos 1

x<0

This therefore does not have a solution within the range 0 ≤ x ≤ 2pi

x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.

For the second option

.cos(x/2)<1

x/2< arccos1

x/2<0

x<0

This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.

For the inequality csc(x)<1

1/sin(x) < 1

1< sin(x)

sinx>1

x>arcsin1

x>90°

x>π/2

This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values

For the inequality csc(x/2)<1

1/sin(x/2) < 1

1< sin(x/2)

sin(x/2)> 1

x/2 > arcsin1

X/2 > 90°

x>180°

x>π

This value of x also has a solution within the range.

Therefore option A is the only inequality that does not have a solution with the range.

6 0
3 years ago
A) Enter the corresponding values on the quadratic formula:
ollegr [7]

The answer is a = 0, b = -5, and c= 39.

<u>Step-by-step explanation</u>:

<u>step 1</u> :

A quadratic equation means that it should have at least one squared term.

<u>step 2</u> :

The standard form is ax² + bx + c = 0.

<u>step 3</u> :

The solution to the quadratic equation is usually written in the form

x = (-b ± √(b2 − 4ac))/(2a)

where a = coefficient of x^2

           b = coefficient of x

          c = constant term

<u>step 4</u> :

The given equation is -5x +32.

∴ The answer is a = coefficient of x^2 = 0

                           b = coefficient of x = -5

                          c = constant term = 39

7 0
3 years ago
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