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Elanso [62]
3 years ago
7

Please help me with this question please

Mathematics
1 answer:
Arturiano [62]3 years ago
5 0
Answer is the last choice

2a-4/1= -a-1/a-4
Cross multiply
(2a-4)(a-4)= -(a-1)
2a^2-8a-4a+16= -a+1
Bring right to left sign change signs
2a^2-8a-4a+16+a-1=0
Combine like terms
2a^2-11a+15=0

a= 2 b= -11 c= 15
Use quadratic formula

-b+-sq rt of b^2-4ac. Divided by 2a

-(-11) +- 11^2-4(2)(15) divided by 2(2)
11+-sq rt 121-120 divided by 4

11+1 /4. 11-1/4
12/4. 10/4
3. , 5/2
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kicyunya [14]

The perimeter of the figure is 58 units

The area of the figure is 130 unit square

Your question is not properly formatted and the diagram required to solve the question is missing.

I've included the appropriate diagram.

To calculate the perimeter of the shape, we simply add up the side lengths of the visible parts of the figure.

Having said that, the perimeter is:

Perimeter = 7 + 8 + 5 + 8 + 3 + 6 + 3 + 5 + 7 + 6

Perimeter = 58

To calculate the area, we use a different approach.

First, we split the figure into 3, we then calculate the area of each sub-figure, and then we add up the calculated areas.

From left to right, we have:

Rectangle 1

Length = 7\\Width = 6

Rectangle 2

Length = 5\\Width = 6+8 = 14

Rectangle 3

Length = 3\\Width = 6

The area of a rectangle is:

Area = Length * Width

So, the area of the figure is:

Area = 7 * 6 + 5 * 14 + 3 * 6

Area = 130

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brainly.com/question/2649416

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