If you think about it, an octagon is made up of 8 triangles. So you first find the area of one triangle then multiply it by 8 for the total area:
A=1/2bh
A=1/2(9.9)(12)
A=59.4
59.4 x 8= 475.2
Therefore the total area for the octagon should be 475.2 units^2
Hope this helps !
The lateral area of the prism is given by:
LA=[area of the two triangles]+[area of the lateral rectangles]
hypotenuse of the triangle will be given by Pythagorean:
c^2=a^2+b^2
c^2=6^2+4^2
c^2=52
c=sqrt52
c=7.211'
thus the lateral area will be:
L.A=2[1/2*4*6]+[6*8]+[8*7.211]
L.A=24+48+57.69
L.A=129.69 in^2
The total are will be given by:
T.A=L.A+base area
base area=length*width
=4*8
=32 in^2
thus;
T.A=32+129.69
T.A=161.69 in^2
Hope this helps:) plz mark brainiest i would really apperciate it
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Answer: x = (sqrt(7) + 2)/3 and
x = ( – sqrt(7) + 2)/3
Explanation:
3x^2 - 4x - 1 = 0
Divide both sides by 3:
3x^2/3 - 4/3x - 1/3 = 0/3
x^2 - 4/3x - 1/3 = 0
x^2 - 4/3x = 1/3
x^2 - 4/3x + (2/3)^2 = 1/3 + (2/3)^2
(x - 2/3)^2 = 1/3 + 4/9
(x - 2/3)^2 = 7/9
Sqrt both sides:
x - 2/3 = sqrt (7/9)
x - 2/3 = |sqrt(7)/3|
Set x -2/3 = sqrt(7)/3
=> x = (sqrt(7) + 2)/3
Set x - 2/3 = - sqrt(7)/3
=> x = ( - sqrt(7) + 2)/3
Answer:
y+3 = -6(x+9)
Step-by-step explanation:
m(x-x1)= (y-y1)
-6[x-(-9)] = [y-(-3)]
-6(x+9) = y+3
.....
<span>Area of square c2 = -area of square a2 - area of square b2 + area of defect1 * area of defect2</span>
