3 years ago

In the right triangle shown, m∠A = 30 degrees, and BC = 6√2, how long is AC?

1 answer:

3 0

They're trying to trick you with √2. Remember in the 30/60/90 triangle the sides are in ratio 1:√3:2, with the "1" opposite the 30 degrees.

Here we have

1:√3:2 = 6√2:x:hypotenuse

x/(6√2) = √3/ 1

x = 6√2×√3 = 6√6

Answer: AC=6√6

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Answer:

$h= \frac{\sqrt{(-a+b+c+d)(a-b+c+d)(a-b+c-d)(a-b-c+d)}}{2|b-a|}$

Step-by-step explanation:

The height (or altitude) is the perpendicular distance between the bases.
In the case that the two bases have different lengths (a ≠ b), the height of a trapezoid h can be determined by the length of its four sides using the formula

$h= \frac{\sqrt{(-a+b+c+d)(a-b+c+d)(a-b+c-d)(a-b-c+d)}}{2|b-a|}$

where c and d are the lengths of the legs.

Keywords: height of trapezoid

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