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3 years ago

How do you solve x-8= -(12/x)

1 answer:

3 0

$x\not=0\\
x-8= -\frac{12}{x}|\cdot x\\
x^2-8x=-12\\
x^2-8x+12=0\\
x^2-6x-2x+12=0\\
x(x-6)-2(x-6)=0\\
(x-2)(x-6)=0\\
x=2 \vee x=6
$

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What is the sum of (2x4 + 5x3 - 8x2 - x + 10) and (8x4 - 4x3 + x2 - x + 2)?

balu736 [363]

Option D: $10x^4+x^3-7x^2-2x+12$ is the right answer

Step-by-step explanation:

Given polynomials are:

$P_1 : 2x^4+5x^3-8x^2-x+10\\P_2: 8x^4-4x^3+x^2-x+2$

We have to find the sum of polynomials

So,

$S = P_1+P_2\\= (2x^4+5x^3-8x^2-x+10) + (8x^4-4x^3+x^2-x+2)\\=2x^4+5x^3-8x^2-x+10+8x^4-4x^3+x^2-x+2\\$

Combining like terms

$=2x^2+8x^4+5x^2-4x^3-8x^2+x^2-x-x+10+2\\= 10x^4+x^3-7x^2-2x+12$

Hence,

Option D: $10x^4+x^3-7x^2-2x+12$ is the right answer

Keywords: Polynomials, sum

Learn more about polynomials at:

#LearnwithBrainly

3 0

3 years ago

Read 2 more answers

The half-life of radium is 1690 years. If 20 grams are present now, how much will be present in 250 years?

Aneli [31]

Answer:

18.05 g

Step-by-step explanation:

The multiplier of the initial quantity is ...

(1/2)^(t/1690)

so, for t=250, this becomes ...

(1/2)^(250/1690) ≈ 0.902545

Then the quantity remaining of the initial 20 g is ...

(20 g)(0.902545) ≈ 18.05 g

3 0

3 years ago

1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6

meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

x= -3

Putting value of x in equation 1

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

$\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$

Let

$\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]$ = A $\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = X and $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$ = B

Then AX= B

or X= A⁻¹ B

where A⁻¹= adj A/ ║A║ where mod A≠ 0

adj A= $\left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]$

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]$ $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}42\\0\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-3\\0\\\end{array}\right]$

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0

3 years ago

Can somebody find the solution to this question

AleksAgata [21]

<h3>Answer: Solution is x = -2</h3>

You have two equations with y1 = f(x) and y2 = g(x).

We're looking for the values of x such that f(x) = g(x). This is the same as trying to solve y1 = y2.

The first row of the table shows y1 and y2 having the same value 5. So we just record the x value that goes with these y values.

5 0

2 years ago

If sales tax in a specific county is 6.5% what is the total price paid on a purchase of $156.00

olasank [31]

Then, it would be 156 + 156*6.5 /100 = 156+10.14 = $166.14

8 0

3 years ago