How do you solve x-8= -(12/x)

1 answer:

3 0

$x\not=0\\
x-8= -\frac{12}{x}|\cdot x\\
x^2-8x=-12\\
x^2-8x+12=0\\
x^2-6x-2x+12=0\\
x(x-6)-2(x-6)=0\\
(x-2)(x-6)=0\\
x=2 \vee x=6
$

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