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Mila [183]
3 years ago
14

How do you solve x-8= -(12/x)

Mathematics
1 answer:
blagie [28]3 years ago
3 0
x\not=0\\
x-8= -\frac{12}{x}|\cdot x\\
x^2-8x=-12\\
x^2-8x+12=0\\
x^2-6x-2x+12=0\\
x(x-6)-2(x-6)=0\\
(x-2)(x-6)=0\\
x=2 \vee x=6

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