Answer:
6ab + b^2 - 17a - 4b + 10
Step-by-step explanation:
-2(a+b-5)+3(-5a+2b)+b(6a+b-8)
Now we break the parenthesis. To break that, we multiply each of the value inside the parenthesis by the adjacent number. That is, for the first part of the expression, we multiply by -2, then by 3, and then by b.
Algebraic Operations need to be considered:
[ (-) x (-) = (+); (-) x (+) = (-)]
= [-(2*a) + (-2*b) - (-2*5)] + [3*(-5a) + (3*2b)] + [(b*6a) + (b*b) - (b*8)]
= -2a - 2b +10 -15a + 6b + 6ab + b^2 - 8b
Now, we will make the adjustment by the similarity value.
= - 2a - 15a - 2b + 6b - 8b + 6ab + b^2 + 10
= - 17a - 4b + 6ab + b^2 + 10
= 6ab + b^2 - 17a - 4b + 10
Therefore, the answer of the expression is = 6ab + b^2 - 17a - 4b + 10
Answer:
p²q³ + pq and pq(pq² + 1)
Step-by-step explanation:
Given
3p²q² - 3p²q³ +4p²q³ -3p²q² + pq
Required
Collect like terms
We start by rewriting the expression
3p²q² - 3p²q³ +4p²q³ -3p²q² + pq
Collect like terms
3p²q² -3p²q² - 3p²q³ +4p²q³ + pq
Group like terms
(3p²q² -3p²q²) - (3p²q³ - 4p²q³ ) + pq
Perform arithmetic operations on like terms
(0) - (-p²q³) + pq
- (-p²q³) + pq
Open bracket
p²q³ + pq
The answer can be further simplified
Factorize p²q³ + pq
pq(pq² + 1)
Hence, 3p²q² - 3p²q³ +4p²q³ -3p²q² + pq is equivalent to p²q³ + pq and pq(pq² + 1)
I’m doing this too hopefully someone answers quick cause I’m confused also.
The playground is a square, so there will be a right triangle formed by diagonal and two sides. So sides length²*2=diagonal length². So the side length is 38.9 meter.
Hypotenuse ^2 = base^2 + perpendicular ^2
H^2 = 6^2 + 8^2
H^2 = 36 + 64
H^2 = 100
H = 10
(This is a right angle triangle as 60+30= 90
180-90= 90)
