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kenny6666 [7]
3 years ago
5

The relative growth rate for a certain type of mutual fund is 5.1% per year. An account is opened with a balance of $35,000. How

much is the mutual fund worth in 5 years? In your final answer, include all of your calculations.
Mathematics
1 answer:
icang [17]3 years ago
3 0
What do you mean by "relative growth rate?"

You need to specify whether this situation involves compounding, and, if it does, whether it's continuous compounding, monthly, annual or what.

Just supposing that it's semi-annual compounding:


A = $35000 (1 + 0.051/2)^(5*2)

   = $35000(1.0255)^10   =   $35000 (1.2863) = $45021.99   (answer)
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Use the quadratic formula to solve x^2-4x+3. Show your work. Then describe the solution
mars1129 [50]
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a= 1, b=-4, and c=3

Therefore, x=(-(-4)+-sqrt((-4)^2-4(1)(3))/(2(1))

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4 0
3 years ago
Can I get help solving this graph please?
Daniel [21]
see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100)  B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40)  C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0)  B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60)  C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then 
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x) 
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then 
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x) 
h'(x)=18/25=0.72 

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0
3 years ago
what is the probability of having one girl and three boys in a 4 child family assuming boys and girls are equally likely
lara31 [8.8K]
The possibilities are:

bbbb

bbbg

bbgg

bggg

This shows that there is a 1 in 4 chance of having three boys and one girl

So the answer could be 1/4 or a 25% chance

5 0
3 years ago
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