Answer:
can you show a link to the graph
Step-by-step explanation:
it will help me answer
Answer:
[0.184, 0.266]
Step-by-step explanation:
Given:
Number of survey n =280
Number of veterans = 63
Confidence interval = 90%
Computation:
Probability of veterans = 63/280
Probability of veterans =0.225
a=0.1
Z(0.05) = 1.645 (from distribution table)
Confidence interval = 90%
So,
p ± Z*√[p(1-p)/n]
0.225 ± 1.645√(0.225(1-0.225)/280)
[0.184, 0.266]
Answer:
0.8
Step-by-step explanation:
cos z = 8/10 = 0.8
Answer:
Option E) 61.6
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 100 bushels per acre
Standard Deviation, σ = 30 bushels per acre
We assume that the distribution of yield is a bell shaped distribution that is a normal distribution.
Formula:

P(X>x) = 0.90
We have to find the value of x such that the probability is 0.90
P(X > x)
Calculation the value from standard normal table, we have,

Hence, the yield of 61.6 bushels per acre or more would save the seed.