How do I solve? What do I do?

Sarah is 3 years older than nine times Mario's age. In 10 years, she will be 1 less than triple his

Natasha2012 [34]

Answer:

3(9m + 13) - (m + 10) = 1

Step-by-step explanation:

Here, we want to write an equation we can use to find the age of Mario.

Let the present age of Mario be M

Age of Sarah is 3 years older than 9

times Mario’s age

Mario’s age is thus;

9m + 3

In ten years, she will be 1 less than triple his age

In 10 years time, sarah age will be 9m +

3 + 10 = 9m + 13

Mario age will be m + 10

Mathematically;

3(9m + 13) - (m + 10) = 1

7 0

2 years ago

1. m∠QPR = 2. m∠QTP = 3. RP = Show all the work

alex41 [277]

Answer:

1. 30°

2.90°

3. 12 units

Step-by-step explanation:

I can't believe there's nothing confirming that this is a parallelogram/a rhombus?! Assuming is awful, and I wish you could say you can't know for sure lol but for the sake of this answer, let's just call it a rhombus. (There was probably some context elsewhere that you didn't put over here, hopefully.)

1.

The reason I say this is: in a rhombus, the diagonals bisect the angles. This means that the diagonals split the angles they meet into two equal parts. That way, it would make sense. m∠QPR=m∠SPR=30°.

2.

If it is a rhombus, the diagonals are perpendicular to each other, so m∠QTP should be 90°.

3.

Diagnonals in a rhombus (and in any parallelogram) bisect each other, so PT=TR=6, and RP=PT+TR=12 units.

Sorry if this is all dreadfully wrong, and I hope I helped you!

7 0

2 years ago

You are designing a rectangular garden. the garden will be enclosed by fencing on three sides and by a house on the fourth side.

RUDIKE [14]

Suppose the dimensions of the rectangle is x by y and let the side enclosed by a house be one of the sides measuring x, then the sides that is to be enclosed are two sides measuring y and one side measuring x.

Thus, the length of fencing needed is given by

P = x + 2y

The area of the rectangle is given by xy,

i.e.

$xy = 288 \\ \\ \\ \\ \Rightarrow y= \frac{288}{x}$

Substituting for y into the equation for the length of fencing needed, we have

$P=x+2\left( \frac{288}{x} \right)=x+ \frac{576}{x}$

For the amount of fencing to be minimum, then

$\frac{dP}{dx} =0 \\ \\ \Rightarrow1- \frac{576}{x^2} =0 \\ \\ \Rightarrow \frac{576}{x^2} =1 \\ \\ \Rightarrow x^2=576 \\ \\ \Rightarrow x=\sqrt{576}=24$

Now, recall that

$y= \frac{288}{x} = \frac{288}{24} =12$

Thus, the length of fencing needed is given by

P = x + 2y = 24 + 2(12) = 24 + 24 = 48.

Therefore, 48 feets of fencing is needed to enclose the garden.

8 0

3 years ago

If a(x) = 3x + 1 and b(x)= √x-4 , what is the domain of (b*a)(x)

kondor19780726 [428]

A(x) = 3x + 1
b(x) = √(x-4)

Therefore
$(b \circ a) (x) = \sqrt{3x+1-4} =\sqrt{3x-3}$
This composition of functions is only defined as a real number when x≥0.
Therefore its domain is x = [1,∞]

Answer: [1,∞]

5 0

2 years ago

Read 2 more answers

Ok So I an taking algebra 1 and this question is really confusing me.

V125BC [204]

You use the arithmetic sequence formula and input the information given to you.
tn = a + (n-1)d
t(56) is what your looking for so don't worry about the tn.
a is your first term,
a = 15.
n is the position of the term you are looking for, n = 56.
And d is the common difference, you find this by taking t2 and subtracting t1. t2=18 and t1=15.
d = 18 - 15 = 3
Inputting it all into the formula you get,
t(56) = 15 + (56-1)(3)
term 56 = 180.
You use this formula to find any term in a sequence provided you are given enough info. You can also manipulate it if you are asked to find something else like the first term(a), common difference(d) or term position(n). It just depends on what the question is asking and what information you are given. :)
Hope this helps!

7 0

3 years ago