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vaieri [72.5K]
3 years ago
8

Area as a sum: Area as a Product: I need the are as a sum Nd a product

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
8 0

Given:

The area model.

To find:

The area as a sum and area as a product.

Solution:

The four terms of the area model are 2x^2,10x, 3x, 15.

The area as a sum is the sum of all the terms of given area model.

Area as a sum = 2x^2+10x+3x+15

                        = 2x^2+13x+15

The area as a product is the factor form of sum of all the terms of given area model.

Area as a product = 2x^2+10x+3x+15

                        = 2x(x+5)+3(x+5)

                        = (x+5)(2x+3)

Therefore, the area as a sum is 2x^2+13x+15 and the area as a product is (x+5)(2x+3).

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<u>Work 1:</u>
   Successful Percent:

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     .75 times 100 is equal to 75
     75%
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100% minus 75% equals 25%
     <em>25%</em>
<u>Work 2:</u><u />
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7 0
3 years ago
<img src="https://tex.z-dn.net/?f=x%20%20%5Cdiv%203x%20-%202%20%3D%201%20%5Cdiv%203x%20-%204" id="TexFormula1" title="x \div 3x
Maurinko [17]

Hello from MrBillDoesMath!

Answer:

x = 1/2 (1 +\- i sqrt(23))

Discussion:

x \3x - 2 =   (x/3)*x - 2   =  (x^2)/3 - 2     (*)

1 \3x - 4   =  (1/3)x - 4                               (**)

(*) = (**)   =>

(x^2)/3 -2 = (1/3)x - 4        => multiply both sides by 3

x^2 - 6 = x - 12                 => subtract x from both sides

x^2 -x -6 = -12                   => add 12 to both sides

x^2-x +6  = 0

Using the quadratic formula gives:

x = 1/2 (1 +\- i sqrt(23))

Thank you,

MrB

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Answer:

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Answer:

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