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eimsori [14]
3 years ago
8

Please help due tomorrow

Mathematics
1 answer:
mel-nik [20]3 years ago
5 0

Answer: x= 2.5, y = 10

Step-by-step explanation:

<u><em>I'm going to assume that these photocopies are proportional in relations to each other.</em></u>

If they're proportional, you can set up two proportions:

1) \frac{x}{5} =\frac{3}{6} \\\\2) \frac{5}{y} =\frac{3}{6}

And cross-multiply:

1) 6x = 5*3 \\\\2) 3y = 5*6

Then solved for x and y:

1) 6x = 15\\x=\frac{15}{6} =\frac{5}{2} =2.5 \\\\2) 3y = 30\\y=\frac{30}{3} =10

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A ball is thrown into the air with an upward velocity of 32 ft/s. Its height (h) in feet after t seconds is given by the functio
Natasha2012 [34]
For this case we have the following equation:
 h = -16t ^ 2 + 32t + 6
 Deriving we have:
 h '= -32t + 32
 We equal zero and clear t:
 -32t + 32 = 0
 32t = 32
 t = 32/32
 t = 1 s
 Then, the maximum height is given by:
 h (1) = -16 * (1) ^ 2 + 32 * (1) + 6
 h (1) = 22 feet
 Answer:
 
It takes the ball to reach its maximum height about:
 
t = 1 s
 
The ball's maximum height is:
 
h (1) = 22 feet
6 0
3 years ago
If y-(1/y)=x then what is y^3-(1/y^3)=?
pogonyaev

Answer: y3−1y3=234

Step-by-step explanation:

y−1y=6

(y−1y)3=63

y3−3y+3y−1y3=216

y3−1y3=216+3(y−1y)=216+3(6)

not sure:)

5 0
3 years ago
Read 2 more answers
There was a triangle that had sides that were 5. 6, 6. 5, and 8.7 inches in length If Rochelle wanted to create a larger triangl
r-ruslan [8.4K]

Answer:

The answer is: 11.2, 13 and 17.4

Step-by-step explanation:

The scale factor of 2 means that we will build a triangle with sides of double lenght than original one.

So sides will be

5.6\times 2=11.2

6.5\times 2=13

8.7\times 2=17.4

6 0
3 years ago
Let f be the function defined as follows:1. If a = 2 and b = 3, is f continuous at x = 1? Justify your answer.2. Find a relation
Arada [10]

Answer:

1. not continuous, as the function definitions deliver different function values at x=1 when approaching this x from the left and from the right side.

2.

2 = a + b

3.

0 = 2a + b

4.

a = -2

b = 4

Step-by-step explanation:

the function is continuous at a specific point or value of x, if the f(x) = y functional value is the same coming from the left and the right side at that point.

1. that means that for x=1

3 - x = ax² + bx

so,

3 - 1 = a×1² + b×1 = a + b

2 = a + b

we have to use a=2 and b=3

2 = 2 + 3 = 5

2 is not equal 5, so the assumed equality is false, so the function is not continuous there.

2. point 1 gave us already the working relationship between a and b.

2 = a + b

only if that is true, is the function continuous at x=1.

3. now for x=2

5x - 10 = ax² + bx

5×2 - 10 = a×2² + b×2 = 4a + 2b

10 - 10 = 4a + 2b

0 = 4a + 2b

0 = 2a + b

4. to find a and b to be continuous at both locations x=1 and x=2 both expressions in a and b must apply.

so, they establish a system of 2 equations with 2 variables.

2 = a + b

0 = 2a + b

a = 2 - b

0 = 2×(2-b) + b = 4 - 2b + b = 4 - b

b = 4

therefore

a = 2 - 4 = -2

5. I cannot draw a graph here.

just use now the function

3 - x, x < 1

‐2x² +4x, 1 <= x < 2

5x - 10, x >= 2

8 0
3 years ago
Pls dears TAKE LCM and SOLVE this question pls HELP​
ivanzaharov [21]

Answer:

L.C.M OF

1) 1/2+1/3+1/5 IS THE L.C.M OF THEIR DINOMINATORS=30

THEREFORE,(15+10+6)/30=31/30

2)1/3 ÷1/2+1/4

=1/3×2/1 +1/4 (D.M.A.S)

=2/3+1/4

=L.CM OF DINOMENATORS 12 AS L.C.M OF 3 AND 4.

(8+3)/12

=11/12

Step-by-step explanation:

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<em>S</em><em>E</em><em>E</em><em> </em><em>S</em><em>O</em><em>L</em><em>U</em><em>T</em><em>I</em><em>O</em><em>N</em><em> </em><em>O</em><em>F</em><em> </em><em>Q</em><em>.</em><em>1</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>2</em><em>.</em><em>.</em><em>.</em>

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6 0
2 years ago
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