There can be zero solutions, 1 solution or infinite solutions
Answer:
Your first step in solving the system would be to substitute the value of a variable into one of the equations
Step-by-step explanation:
We know that x = 2y + 2 and y = -1/3x + 4, so we could insert one of these values as the variable in one of the equations
If we were to insert -1/3x + 4 for y, our new equation would be:
x = 2(-1/3x + 4) + 2 (as you can see, the value of y was inserted into the equation)
The answer is 81.75. 54 1/2 divided by 2/3
We need Pythagoras theorem here
a^2+b^2 = c^2
a, b = legs of a right-triangle
c = length of hypotenuse
Let S=shorter leg, in cm, then longer leg=S+2 cm
use Pythagoras theorem
S^2+(S+2)^2 = (10 cm)^2
expand (S+2)^2
S^2 + S^2+4S+4 = 100 cm^2 [collect terms and isolate]
2S^2+4S = 100-4 = 96 cm^2
simplify and form standard form of quadratic
S^2+2S-48=0
Solve by factoring
(S+8)(S-6) = 0 means (S+8)=0, S=-8
or (S-6)=0, S=6
Reject nengative root, so
Shorter leg = 6 cm
Longer leg = 6+2 cm = 8 cm
Hypotenuse (given) = 10 cm
