3 years ago

Solve for f please :)

Mathematics

1 answer:

kkurt [141]3 years ago

6 0

The answer is A) i think

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CALC!! Please help me. For which pair of functions f(x) and g(x) below will the limit as x goes to infinity of the product of f

Marizza181 [45]

First limit:
$\lim_{x\to\infty}(10x+e^{-x})*\frac{1}{5x}$
$=\lim_{x\to\infty}(2+\frac{1}{5xe^{x}})$
$=2+0$
$=2$

Since we know that the first pair of functions does not approach 0, we do not have to check the others.

6 0

3 years ago

For which pair of functions is the vertex of k(x)7 units below the vertex of f(x)?

kvv77 [185]

Answer: Option C

$f(x) = x^2;\ k (x) = x ^ 2 -7$

Step-by-step explanation:

Whenever we have a main function f(x) and we want to transform the graph of f(x) by moving it vertically then we apply the transformation:

$k (x) = f (x) + b$

If $b> 0$ then the graph of k(x) will be the graph of f(x) displaced vertically b units down.

If $b> 0$ then the graph of k(x) will be the graph of f(x) displaced vertically b units upwards.

In this case we have

$f (x) = x ^ 2$

We know that this function has its vertex in point (0,0).

Then, to move its vertex 7 units down we apply the transformation:

$k (x) = f (x) - 7\\\\k (x) = x ^ 2 -7$ .

Then the function k(x) that will have its vertex 7 units below f(x) is

$k (x) = x ^ 2 -7$

3 0

3 years ago

A. y= -4/5x+ 5/4 B. y= -4/5x+ 3/2 C. y= -5/4x+ 3/2 D. y= -5/4x+ 5/4

Effectus [21]

The answer is C and here are the steps

7 0

3 years ago

The machinist's goal was to increase his production by at least 10% each day. Assume he achieved his goalIf he was able to machi

Semmy [17]

25 x 0.1 = 2.5 ≈ 3

25 + 3 = 28

The machinist would make about 28 on Wednesday

7 0

3 years ago

Given ∆ABC≅∆PQR, mb=8v-9 , find m 31° b. 52° c. 49° d. 32°

Ipatiy [6.2K]

Here, 5v+6 = 8v-9
8v - 5v = 6 + 9
3v = 15
v = 15/3
v = 5

So, m<b = 5(5) + 6 = 25 + 6 = 31
As they are congruent, m<q would be same [ 31 degree ]

In short, Your Answer would be Option A

Hope this helps!

3 0

3 years ago