Apply the elimination method to the 2y terms since they are opposites & therefore can eliminate. Combine the rest of the terms, vertically.
x-2y= -7
4x+2y= 22
5x = 15
Divide both sides by 5.
x=3
Plug the x value to one of the original equations and solve for y.
4x + 2y = 22
4(3) + 2y = 22
12 + 2y = 22
Subtract by 12 on both sides.
2y = 10
Divide by 2 on both sides.
y = 5
Therefore, the solution to the system of equations shown is:
x=3 y=5
or
as an ordered pair (3, 5).
Sec(theta) = 1.3591392 => cos(theta) = 1 / 1.3591392 = 0.7357598103
=> theta = arccos (0.7357598103) = 0.744 rad = 42.6285 degress
Y=7/4x+9/7 is an equation perpendicular to that
The given function is greater than or equal to 0 for the interval given as follows:
{x | x ≤ -3 or -1 ≤ x ≤ 0 or x ≥ 2}.
<h3>When a function is positive and when it is negative?</h3>
- A function is positive when it is above the x-axis.
- A function is negative when it is below the x-axis.
For this problem, with a closed interval, we have that the function is above for:
x ≤ -3, -1 ≤ x ≤ 0, x ≥ 2.
Hence the interval notation is:
{x | x ≤ -3 or -1 ≤ x ≤ 0 or x ≥ 2}.
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