You have to do it to see the results
mass defect = mass of constituents - mass of atom
N has 7p and 9n
proton mass ~ 1.00728 amu
neutron mass ~ 1.00866 amu
electron mass ~ 0.000549 amu
Nitrogen mass ~ 14.003074 amu
mass defect = (7*1.00728)-(7*1.00866)-(7*0.000549)
- 14.003074
= 0.11235amu
convert to energy, the binding energy = 1.68x10^-11 J
Answer:
Na is the element from the second period that has the largest atomic radius
Explanation:
The atomic radius is a chemist property from the periodic table. It is decreased when we move in a period from the periodic, so the element in the second period that has the largest radius is Na, and the shortest, the Ar
The atomic radius indicates the distance between the nucleus and the outermost valence layer. In the periods it decreases with increasing Atomic Number, to the right, due to the attraction that the nucleus exerts on the electrons of the outermost orbitals, thus decreasing the core-electron distance.
Answer:
B) CH3CH2CH2F
Explanation:
All the other compounds listed among the options are capable of forming hydrogen bonds with water except CH3CH2CH2F.
Recall that hydrogen bonds are formed when hydrogen is directly bonded to a highly electronegative atom such as nitrogen, oxygen, fluorine, sulphur, et cetra.
Such bonds are not present in CH3CH2CH2F, rather fluorine is bonded to carbon to give a halogenoalkane. This compound will display the least solubility in water.
