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Semenov [28]
3 years ago
11

Co-60 has a half life of 10.48 minutes. How long will it take for the isotope to decay to 1/64th of its original quantity?

Chemistry
1 answer:
madreJ [45]3 years ago
4 0

Answer:

The answer to your question is: 62.88 min

Explanation:

Data

Co - 60

half-life = 10.48 min

decay = 1/64 th

Process

1      

2     1 half life              1/2                         10.48

3     2 half life             1/4                         20.96

4     3 half life             1/8                         31.44

5     4 half life             1/16                        41.92

6     5 half life             1/32                       52.4

7      6 half life            1/64                        62.88

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(a) C_5H_8O_2

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(a) For the lucite, one computes the moles of C, H and O that are present:

n_C=0.599gC*\frac{1molC}{12gC}=0.05molC\\n_H=0.0806gH*\frac{1molH}{1gH}=0.0806molH\\n_O=0.32gO*\frac{1molO}{16gO}=0.02molO\\

Now, dividing each moles by the smallest moles (oxygen's moles), one obtains:

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C_5H_8O_2

(b) For the Saran, one computes the moles of C, H and Cl that are present:

n_C=0.248gC*\frac{1molC}{12gC}=0.021molC\\n_H=0.02gH*\frac{1molH}{1gH}=0.02molH\\n_{Cl}=0.731gCl*\frac{1molCl}{35.45gCl}=0.021molCl\\

Now, dividing each moles by the smallest moles (hydrogen's moles), one obtains:

C=\frac{0.021}{0.02} =1;H=\frac{0.02}{0.02} =1;Cl=\frac{0.021}{0.02} =1

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(c) For the polyethylene, one computes the moles of C and H that are present:

n_C=0.86*\frac{1molC}{12gC}=0.072molC\\n_H=0.14gH*\frac{1molH}{1gH}=0.14molH

Now, dividing each moles by the smallest moles (carbon's moles), one obtains:

C=\frac{0.072}{0.072} =1;H=\frac{0.14}{0.072} =2

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(d) For the polystyrene, one computes the moles of C and H that are present:

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Now, dividing each moles by the smallest moles (either carbon's or hydrogen's moles), one obtains:

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(e) For the orlon, one computes the moles of C, H and N that are present:

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Now, dividing each moles by the smallest moles (nitrogen's moles), one obtains:

C=\frac{0.057}{0.019} =3;H=\frac{0.057}{0.019} =3;N=\frac{0.019}{0.019} =1

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