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Semenov [28]
3 years ago
11

Co-60 has a half life of 10.48 minutes. How long will it take for the isotope to decay to 1/64th of its original quantity?

Chemistry
1 answer:
madreJ [45]3 years ago
4 0

Answer:

The answer to your question is: 62.88 min

Explanation:

Data

Co - 60

half-life = 10.48 min

decay = 1/64 th

Process

1      

2     1 half life              1/2                         10.48

3     2 half life             1/4                         20.96

4     3 half life             1/8                         31.44

5     4 half life             1/16                        41.92

6     5 half life             1/32                       52.4

7      6 half life            1/64                        62.88

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The complete orbital notation diagram of an atom is shown.
Elan Coil [88]

values of the quantum numbers: -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6

location of the electron: In the 7th energy level away from the nucleus.

Explanation:

From the description of the problem, the magnetic number is given is as -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6 and the electron is located in the 7th energy level away from the nucleus. Basically, the problem is testing for the understanding of the principal quantum numbers which gives the location of electrons and the magnetic quantum number that shows the spatial orientation of the orbitals.

           The orbital designation of the describe electron is 7d

  1. Magnetic quantum number is limited by the azimuthal quantum number which is the quantum number describing the possible shapes. The azimuthal is given as L= n-1. "n" is the principal quantum number which is 7. Therefore L is 6 and the magnetic quantum numbers are -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6
  2. The position of the electron is given by the principal quantum number which represents the main energy level in which the orbital is located or the average distance from the nucleus. Here it is 7.

Learn more:

brainly.com/question/9288609

#learnwithBrainly

5 0
3 years ago
Which statement goes against the kinetic theory of gases?
AURORKA [14]

the answer is c. Gas molecules will never collide with the walls of the container

8 0
3 years ago
Read 2 more answers
What evidence supports a conservation law? 6 CO2 → C6H12O6 6 O2 6 CO2 6 H2O light → C6H12O6 6 O2 6 H2O light → C6H12O6 6 O2 6 CO
docker41 [41]

The law of conservation has been stated that the mass and energy has neither be created nor destroyed in a chemical reaction.

The law of conservation has been evident when there has been an equal number of atoms of each element in the chemical reaction.

<h3>Conservation law</h3><h3 />

The given equation has been assessed as follows:

  • \rm 6\;CO_2\;\rightarrow\;C_6H_1_2O_6

The reactant has absence of hydrogen, while hydrogen has been present in the product. Thus, the reaction will not follow the law of conservation.

  • \rm 6\;O_2\;+\;+\;6\;CO_2\;+\;6\;H_2O\;+\;Light\;\rightarrow\;C_6H_1_2O_6

The number of atoms of each reactant has been different on the product and the reactant side. Thus, the reaction will not follow the law of conservation.

  • \rm 6\;O_2\;+\;6\;H_2O\;+\;Light\;\rightarrow\;C_6H_1_2O_6

The reactant has the presence of carbon, while it has been absent in the reactant. Thus, the reaction will not follow the law of conservation.

  • \rm 6\;O_2\;+\;6\;CO_2\;\rightarrow\;3\;C_6H_1_2O_6\;+\;3\;O_2

The product has the presence of hydrogen, while it has been absent in the reactant. Thus, the reaction will not follow the law of conservation.

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4 0
2 years ago
How many grams of sodium ions are in na2so4?
LiRa [457]

Answer:

142.04

Explanation:

4 0
3 years ago
If a piece of aluminum with a mass of 3.99 g and a temperature of 100.0 °C is dropped
Vinil7 [7]

Answer:

The final temperature of the system is 27.3°C.

Explanation:

Heat lost by aluminum = 3.99 × 0.91 × (100-T)

                                     = 3.631 (100-T)

Heat gained by water = 10 × 4.184 × (T-21)

                                    = 41.84 (T-21)

As,

                                Heat gained = Heat loss

                          or, 3.631(100-T) = 41.84(T-21)

                          or,363.1 -  3.631 T = 41.84 T - 878.64)

                          or, (41.84+ 3.631) T = 878.64 +363.1

                          or  T= \frac{1241.74}{45.47}

                         or, T = 27.3°C

Hence the final temperature is 27.3°C.

8 0
3 years ago
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