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kiruha [24]
2 years ago
7

True or

Chemistry
1 answer:
Alekssandra [29.7K]2 years ago
8 0

The statement that the concentration of carbon will not change if gaseous water is added to the system is false. The concentration of carbon will increase.

<h3>What is concentration? </h3>

Concentration of a substance is the present of a substance in a per-unit square of an area. It is the total amount of solute present in the solution.

The equilibrium is C(s) + H₂O(g) < - > CO(g) + H₂(g), ΔH = 2296 J.

If we increase or add the gaseous water in the system, the amount of carbon will increase because the carbon is a gas, and increasing the pressure will increase the volume of the gas, at Constant temperature.

Thus, the statement is false.

To learn more about concentration, refer to the link:

brainly.com/question/16942697

#SPJ4

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Grams smallest to kilograms and milligrams
Anna007 [38]
Grams is smaller than kilograms but larger than milligrams

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1g = 1000 mg

Grams is an SI unit for mass.

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4 0
3 years ago
An experiment was conducted with a 1.57 gram starting mass of copper. How many grams of cooper were collected if the yield was 8
IRINA_888 [86]

Answer:

1.26 g of Cu

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7 0
3 years ago
The balanced equation for the reaction of aqueous Pb(ClO3)2 with aqueous NaI is Pb(ClO3)2(aq)+2NaI(aq)⟶PbI2(s)+2NaClO3(aq) What
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Answer : The mass of PbI_2 precipitate produced will be, 9.681 grams.

Explanation : Given,

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Volume of solution = 0.2 L

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First we have to calculate the moles of NaI.

\text{Moles of }NaI=\text{Molarity of }NaI\times \text{Volume of solution}=0.210M\times 0.2L=0.042moles

Now we have to calculate the moles of PbI_2.

The balanced chemical reaction is,

Pb(ClO_3)_2(aq)+2NaI(aq)\rightarrow PbI_2(s)+2NaClO_3(aq)

From the balanced reaction we conclude that

As, 2 moles of NaI react to give 1 mole of PbI_2

So, 0.042 moles of NaI react to give \frac{0.042}{2}=0.021 moles of PbI_2

Now we have to calculate the mass of PbI_2.

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\text{Mass of }PbI_2=(0.021mole)\times (461.01g/mole)=9.681g

Therefore, the mass of PbI_2 precipitate produced will be, 9.681 grams.

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