Answer:
64.7g
Explanation:
The balanced chemical equation of this question is as follows;
AlI + HgCl2 → HgI + AlCl2
Based on the above equation, 1 mole of AlI (aluminum monoiodide) reacts to produce 1 mole of HgI (mercury iodide).
Using mole = mass/molar mass to convert mass of HgI to moles.
Molar mass of HgI = 200.59 + 127
= 327.59g/mol
Mole = 138/327.59
= 0.42mol
- If 1 mole of AlI (aluminum monoiodide) reacts to produce 1 mole of HgI (mercury iodide)
- Then 0.42 mol of HgI will be produced by 0.42mol of AlI.
Using mole = mass/molar mass
Mass = mole × molar mass
Molar mass of AlI = 27 + 127
= 154g/mol
Mass of AlI = 0.42 × 154
= 64.7g of AlI
First, we calculate the number of moles of each reactant using the formula:
Moles = mass / molecular weight
CaO:
Moles = 7.15/56 = 0.128
Water:
Moles = 152/18 = 8.44
The reaction equation shows that the reactants must be present in an equal number of moles, so CaO will be the limiting reactant and 0.128 mole of calcium hydroxide will form.
The energy released is given by:
Heat of reaction * number of moles
= -64.8 * 0.128
= -8.29 kJ
8.29 kJ of energy will be released
Answer:
Lithium selenide Lithium selenide (Li2Se) 12136-60-6 Dilithium selenide lithium selenidolithium
Molecular Weight 92.9 g/mol
Dates Modify 2020-11-15 Create 2005-08-08