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kirill [66]
3 years ago
9

PLEAS HELP ME :) (Above)

Mathematics
2 answers:
Naddika [18.5K]3 years ago
8 0

Answer:

A) 137/219

Step-by-step explanation:

The total number of students in the sample  = 219

The total number of students in the 23+ category = 137

Finally, the fraction of students in the 23 + category to that of the total sample

is 137/219

Aleksandr-060686 [28]3 years ago
5 0
I don’t understand it ;(
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Pls show work?!!!!!!!
Paraphin [41]

Answer: 55.5 (A.)

Step-by-step explanation:

Since angle A = 29 and angle B = 41, angle C must be equal to 110

180 = m<A + m<B + m<C

180 = 29 +41 + m<C

180 = 70 + m<C

110 = m<C

Therefore, side c must be the longest, side b must be the second longest, and side a must be the shortest.

Since side length a, angle A, and angle B are known, one can use the law of sines to solve for side b.

Law of Sines: sinA/a = sinB/b = sinC/c

sinA/a = sinB/b

sin29/41 = sin41/b

b(sin29/41) = sin41

b = 41(sin41)/(sin29)

b = 55.48

b = 55.5

7 0
2 years ago
PLEASE!!!!!!!The adjoining figure shows two circles with the same center. The
Nookie1986 [14]
<h3><u>Answer:</u></h3>

\boxed{\boxed{\pink{\sf \leadsto Hence \ the \ area \ of \ shaded \ region \ is 264 cm^2}}}

<h3><u>Step-by-step explanation:</u></h3>

Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.

From the figure it's clear that the area of shaded region will be the difference of areas of two circles.

Let the,

  • Radius of smaller circle be r .
  • Radius of smaller circle be r .
  • Area of shaded region be \bf Area_{shaded}

\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2  \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2)  \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2]  \\\\\bf\implies Area_{shaded}  = \pi [ 100cm^2-16cm^2]  \\\\\bf\implies Area_{shaded}  = \pi \times 84cm^2  \\\\\bf\implies Area_{shaded}  = \dfrac{22}{7}\times 84cm^2  \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}

<h3><u>Hence </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> the</u><u> </u><u>shaded </u><u>region</u><u> is</u><u> </u><u>2</u><u>6</u><u>4</u><u> </u><u>cm²</u><u>.</u></h3>

5 0
3 years ago
Need help asap ..! please and thank you
Hunter-Best [27]
The slope of the line is positive
7 0
3 years ago
Identify this conic section. 16y = x^2
kiruha [24]

ANSWER

A parabola.

EXPLANATION

The given conic is :

16y =  {x}^{2}

This can be rewritten as:

{x}^{2}  = 16y

{x}^{2}  = 4(4)y

This is a parabola with the vertex at the origin.

The foci is (0,4)

Therefore the given conic section is a parabola that has an axis of symmetry parallel to the y-axis.

7 0
3 years ago
What value could be added to 2/15 to make the sum greater than 1/2
Lera25 [3.4K]
1/2 - 2/15= 15-4/30 = 11/30  this means that if you were to add 11/30 to 2/15 is exactly equal to 1/2, to fully answer your question you can use any value above that like 12/30 (keep in mind you have to simplify) = 6/15 = 2/5. But then again your question says to add any number to make it greater than 1/2 so technically you could just add 100 or 200 or 1/2 to make the sum of it greater than one half
7 0
3 years ago
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