Answer:
The equation you are given is a quadratic. The standard form of a quadratic is y = a(x-h)2 + k where (h,k) is the vertex of the graph, which is a parabola. Vertically moving the graph 4 units upward means that you are moving k +4 units.
y = a(x-h)2 + k standard form
y = 5x2 - 4 original equation
y = 5(x-0)2 - 4 re-written in standard form
h = 0 k = -4
Four (4) units up is k + 4--->-4 + 4 = 0.
Therefore, f(x) = 5x2 + 0--->f(x) = 5x2.
Step-by-step explanation:
hope this helps
plz mark brainliest
Answer:
a. Point S
b. Line segment PT and Line segment ST
c. PSQRU
d. Lines PR and SQ
e. Plane C and Plane QRS
Step-by-step explanation:
Answer:20
Step-by-step explanation:
2(3-4)-(8+3)
2(1)-(11)
2-22
Note: I just noticed that you only have one negative sign. If you mean to put -9, change the sign to positive. If not, leave the answer.
Note the equal sign. what you do to one side, you do to the other. Isolate the x. First, multiply 3 to both sides
-x/3(3) = 9(3)
-x = 9(3)
-x = 27
Next, to isolate the x, divide -1 from both sides
-x/-1 = 27/-1
x = 27/-1
x = -27
-27 is your answer for x.
hope this helps
Refer to the diagram shown below.
Because ΔABC is isosceles and AB = AC, therefore
m∠C = m∠B = (3x + 5)°
The sum of angles in a triangle is 180°, therefore
2(3x + 5) + 2x - 20 = 180
6x + 10 + 2x - 20 = 180
8x - 10 = 180
8x = 190
x = 23.75°
Therefore
m∠C = 3x + 5 = 3(23.75) + 5 = 76.25°
Answer: 76.25°