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saul85 [17]
3 years ago
8

An AutoCAD drawing has a scale of 3/4 inches to 2 ft. If a piece of a bridge measures 15 feet, how long is that piece in the Aut

oCAD printout?
11.25 inches

5.625 inches

22.5 inche

51 inches
Please I really need this for tonight
Mathematics
1 answer:
Anna [14]3 years ago
5 0
The answer is B) 5.625 inches
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4/y+2 - 9/y-2 = 9/y^2-4
Evgesh-ka [11]
Going off the idea that this is 4/(y+2) - 9/(y-2) = 9/(y^2-4), let's first rewrite y^2-4 in the form of a^2-b^2, where a=y and b=2.
y/(y+2)-9/(y-2)=9/(y^2-2^2)
Now, use difference of squares: a^2-b^2=(a+b)(a-b)
4/(y+2)-9/(y-2)=9/((y+2)(y-2))
Multiply both sides by the Least Common Denominator: (y+2)(y-2)
4(y-2)-9(y+2)=9
Then keep on simplifying until you get your answer
-5y-26=9
-5y=9+26
-5y=35
y=35/-5
y=-7
Yay! Our answer is y=-7!
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I believe the answer is C
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The 7th grade class is going
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the answer is 30 dollars

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What is 11/12times 13/14
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Data are drawn from a bell-shaped distribution with a mean of 25 and a standard deviation of 4. There are 1,000 observations in
Delicious77 [7]

Answer:

a. 97.72% of the observations are less than 33

b. Approximately 977 observations are less than 33.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 25 and a standard deviation of 4.

This means that \mu = 25, \sigma = 4

a. Approximately what percentage of the observations are less than 33?

The proportion is the p-value of Z when X = 33. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{33 - 25}{4}

Z = 2

Z = 2 has a p-value of 0.9772

0.9772*100% = 97.72%

97.72% of the observations are less than 33.

b. Approximately how many observations are less than 33?

Out of 1000:

0.9772*1000 = 977.2

Approximately 977 observations are less than 33.

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3 years ago
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