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vekshin1
3 years ago
5

If the person borrowed $3000 for 3 years at a rate of 2%, how much interest will they owe for the loan

Mathematics
1 answer:
krek1111 [17]3 years ago
3 0

In this case were going to solve the question using "simple interst", so since were looking for the interest it will be I= PxRxT (I stands for "interest", P stands for "principal", R stands for "rate" and T stands for "time")

so P is $3000

R is 2%

and T is 3 years

so we'll have to turn our rate into a decimal which is 2% = .02

now to start the problem:

I= (3000)(.02)(3)       (means 3000 x .02 x 3)

I= $180  is your answer


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Answer:

I can help with Q "4" as -

It uses triangle congruence test -  here we use - SAS, as

one side is equal as it is given

both the  angles are 90 degree

and they share a same side

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8x = 6x + 5

8x - 6x = 5

2x = 5

x = 2.5

RU = 6x+ 5 = 6 (2.5) + 5 = 20

( I am not so sure but I think this is the answer )

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3 years ago
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olya-2409 [2.1K]
I'll go with A and B 

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Please answer the question in the image below ASAP
attashe74 [19]
Option A would run parallel because they have the same slope.
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3 years ago
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Write the equation of the line passing through the point ​(​6,-9​) with slope -5/6.
Brilliant_brown [7]

Answer:

The equation is y = -5/6 x-4

Step-by-step explanation:

The equation of a line in slope intercept form is

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y = -5/6 x+b

Substitute in the point

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3 0
2 years ago
A coin is tossed twice. What is the probability of getting a tail in the first toss and a tail in the second toss?
skelet666 [1.2K]

Answer:

<h2>1/4 Chances</h2><h2>25% Chances</h2><h2>0.25 Chances (out of 1)</h2>

Step-by-step explanation:

Two methods to answer the question.

Here are presented to show the advantage in using the product rule given above.

<h2>Method 1:Using the sample space</h2>

The sample space S of the experiment of tossing a coin twice is given by the tree diagram shown below

The first toss gives two possible outcomes: T or H ( in blue)

The second toss gives two possible outcomes: T or H (in red)

From the three diagrams, we can deduce the sample space S set as follows

          S={(H,H),(H,T),(T,H),(T,T)}

with n(S)=4 where n(S) is the number of elements in the set S

tree diagram in tossing a coin twice

The event E : " tossing a coin twice and getting two tails " as a set is given by

          E={(T,T)}

with n(E)=1 where n(E) is the number of elements in the set E

Use the classical probability formula to find P(E) as:

          P(E)=n(E)n(S)=14

<h2>Method 2: Use the product rule of two independent event</h2>

Event E " tossing a coin twice and getting a tail in each toss " may be considered as two events

Event A " toss a coin once and get a tail " and event B "toss the coin a second time and get a tail "

with the probabilities of each event A and B given by

          P(A)=12 and P(B)=12

Event E occurring may now be considered as events A and B occurring. Events A and B are independent and therefore the product rule may be used as follows

        P(E)=P(A and B)=P(A∩B)=P(A)⋅P(B)=12⋅12=14

NOTE If you toss a coin a large number of times, the sample space will have a large number of elements and therefore method 2 is much more practical to use than method 1 where you have a large number of outcomes.

We now present more examples and questions on how the product rule of independent events is used to solve probability questions.

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2 years ago
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