Answer:
The answer in the procedure
Step-by-step explanation:
Let
A1 ------> the area of the first square painting
A2 ----> the area of the second square painting
D -----> the difference of the areas
we have
case 1) The area of the second square painting is greater than the area of the first square painting
The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting
D=A2-A1
case 2) The area of the first square painting is greater than the area of the second square painting
The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting
D=A1-A2
Answer:
-1
Step-by-step explanation:
equation:
3(5-4)-4(5-4)
3*5-3*4 -4*5-4*-4
15-12-20+16
3-4
-1
Answer:
P=41.72
Step-by-step explanation:
S=ACxDB/2
81.7=8.6xDB/2
81.7=4.3xDB|:4.3
19(mm)=DB
DO=19/2=9.5
OC=8.6/2=4.3
(O is the center of the rhombus, where two diagonals meet)
a²+b²=c² (DO²+OC²=DC²)
9.5²+4.3²=c²
90.25+18,49=c²
√108,74=√c²
c≈10.43
P=4c
P=4x10.43
P=41.72
Hope it helps:)
The probability of wearing blue shirts on both days is 3/28.
<h3>What is probability?</h3>
Probability is the measure of the likelihood of an occurrence.
Given:
8 shirts are available out of which 3 are blue, 1 is green and 2 are white.
P(blue on Monday) = 3/8
Now, 7 shirts are left to wear on Tuesday
P(blue on Tuesday) =2/7
So,
the probability of wearing blue shirts on both days = 3/8 * 2/7 = 3/28
Learn more about probability here:
brainly.com/question/24756209
#SPJ1
12 is a factor of 36 and of course 12, so
Answer: 12
