Answer:
Let's assume John gets p for each day so his total is 4p. He spends half of that on gas, (4p)/2 = 2p. He has 2p left. Now subtract 5 from 2p for the coffee, and there is 35 left. So 2p - 5 = 35. Right? Now you can solve for p, by simplifying that equation.
Step-by-step explanation:
Answer:
The answer is 23.
Step-by-step explanation:
Our equation here is (2x + y) + 5.
If x=4, and y=10, let's plug that in into our variables, and simplify!
[2(4) + (10)] + 5
= [8+10] + 5
=[18] +5
=23
Answer:
<h2>There is 8% probability of Kitzen winning first and Ava second.</h2>
Step-by-step explanation:
The given table shows that there are 4 students, so there are 4 possible winner in total, but they have different number of tickets.
The total number of tickets is 48, that's the total possible outcomes. Kitzen has a probability of
![P_{Kitzen}=\frac{12}{48}=\frac{1}{4}](https://tex.z-dn.net/?f=P_%7BKitzen%7D%3D%5Cfrac%7B12%7D%7B48%7D%3D%5Cfrac%7B1%7D%7B4%7D)
Ava has a probability of
![P_{Ava}=\frac{16}{48}=\frac{1}{3}](https://tex.z-dn.net/?f=P_%7BAva%7D%3D%5Cfrac%7B16%7D%7B48%7D%3D%5Cfrac%7B1%7D%7B3%7D)
Now, the probability of having one event and the other is
![P=\frac{1}{4} \times \frac{1}{3}=\frac{1}{12} \approx 0.08](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B1%7D%7B4%7D%20%5Ctimes%20%5Cfrac%7B1%7D%7B3%7D%3D%5Cfrac%7B1%7D%7B12%7D%20%5Capprox%200.08)
Therefore, there is 8% probability of Kitzen winning first and Ava second.
(Notice that the probaility is not about Kitzen or Ava winning, it's about winning both, that's why the percentage is low)
Answer:
<em>6</em>
Step-by-step explanation:
<em>hold up hold up so you are saying 60 less than what quotient I'm guessing 68 divided by 12 so the answer would be 6</em>