Answer:
A C(x) =2x³+2x²-18x-11
Step-by-step explanation:
C(x) = W(x) - D(x)
plug W(x) and D(x) into equation
C(x) = 3x³+4x²-18x+4 - (x³+2x²+15)
add like terms now
C(x) =2x³+2x²-18x-11
By the definition, An observed value of \bar{x} to estimate the mean of population is a point estimate and the statistic \bar{x} is a poiont estimator.
It is given that, "Hen 430 randomly selected light bulbs were tested in a laboratory"
That is, the Random sample size n= 430
The statement given that, "224 lasted more than 500 hours"
So x=224
Now find a point estimate of the last more than 500 hours proportion of all light bulbs:
Thus
This implies that
Thus the answer is D: 0.521.
Your answer should be C.
Let me know if you have any questions :)