Answer:
The box contains 20 milk chocolates.
Step-by-step explanation:
Given that the chocolate box has milk chocolates and dark chocolates in a ratio of 2 milk chocolates for every 3 dark, and the total number of chocolates in the box is 50 units, to determine how many milk chocolates are in the box. it is necessary to perform the following calculation:
50 / (2 + 3)
50/5
10
Milk chocolates: 2 x 10 = 20
Dark chocolates: 3 x 10 = 30
Therefore, the box contains 20 milk chocolates.
Answer:
(a^8)/(b^9)
Step-by-step explanation:
Two rules of exponents come into play.
(a^b)/(a^c) = a^(b-c)
a^-b = 1/a^b
__
Applying the first rule, we have ...
(a^3)/(a^-5) × (b^-2)/(b^7) = a^(3 -(-5)) × b^(-2 -7) = a^8 × b^-9
Applying the second rule gives the simplified form ...
= (a^8)/(b^9)
Let
N--------> <span>members of the club
we know that
($192/(N+2)=3.20
192=(N+2)*3.20
3.20*N+6.40=192
3.20*N=192-6.40
N=185.60/3.20
N=58
the answer is
58</span>
Answer:
Step-by-step explanation:
It would be A, the first one.
F(x) = 50x + 20
y= 50x + 20
120 = 50(2) + 20
0 <(or equal to) x <(or equal to) 2