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2 years ago

What is the value of the slope of a line with the equation: 20-5x?

Mathematics

1 answer:

alina1380 [7]2 years ago

7 0

Answer:

-5

Step-by-step explanation:

the slope is the variable in front of the x

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Standard form of two hundred ten million, sixty four thousand,fifty

neonofarm [45]

We have to write the standard form of : two hundred ten million, sixty four thousand , fifty.
210 * 10,000,000 + 64 * 10,000 + 50
Answer:
The standard form is 210,064,050.

7 0

3 years ago

0=9x-9x no solution, one solution, infinite solutions

attashe74 [19]

Answer:

0 = 9x - 9x

0 = 0

This means it has infinite number of solutions.

Step-by-step explanation:

<h2>HOPE IT HELPS U!!!!</h2>

4 0

2 years ago

What is the greatest common factor of 54,30,78? pleaseeeeee help lol

Contact [7]

$Greatest\ common\ factor\ is\ the\ highest\ number\ by\ witch\ 54\ and\ 30\\and\ 78\ can\ be\ divided\\\\
54:2\\
27:3\\9:3\\3:3\\\\
30:2\\
15:3\\
5:5\\\\78:2\\39:3\\13:13
\\\\GCF=2*3=6\\\\Greatest\ common\ factor\ of\ 54\ and\ 30\ and\ 78\ is\ equal\ to\ 6.
$

5 0

2 years ago

Urgent will mark brainliest

Luda [366]

First, isolate the variable:

x>-33

The answers would be 25, 14, -25.

I am not sure if that is a more than sign or a more than or equals sign; if it is a more than sign the answers mentioned above are the only answers, but if it a more than or equals sign, the answers are 25, 14, -25, -33.

If it helped please consider giving be brainliest :)

7 0

2 years ago

Read 2 more answers

A biologist is studying the growth of a particular species of algae. She writes the fall inclusion to show the radius of the alg

horrorfan [7]

Answer:

Part A)

A reasonable domain to plot the growth function is:

$0\leq d \leq 12$

Part B)

The y-intercept represents that when the biologist started her study, the radius of the algae was five millimeters.

Part C)

The average rate of change from d = 4 to d = 11 was about 0.11. This means that from the 4th day to the 11th, the radius of the algae grew, on average, at a rate of 0.11 mm per day.

Step-by-step explanation:

The radius of the algae f(d) in millimeters after d days is given by the function:

$f(d)=5(1.02)^d$

Part A)

We know that the radius of the algae was approximately 6.34 mm when the biologist concluded her study. To find the reasonable domain, we can substitute 6.34 for f(d) and solve for d. Therefore:

$6.34=5(1.02)^d$

Divide both sides by five:

$(1.02)^d=1.268$

Take the log of both sides with base 1.02:

$\displaystyle d=\log_{1.02}1.268$

Using the Change of Base Property, evaluate for d:

$\displaystyle d=\frac{\log 1.268}{\log 1.02}=11.9903...\approx 12$

So, the biologist concluded her study after 12 days.

Therefore, a reasonable domain to plot the growth function is:

$0\leq d\leq 12$

Part 2)

The y-intercept of the function is when d = 0. Find the y-intercept:

$f(0)=5(1.02)^{(0)}=5(1)=5$

Since d represent the amount of days after the study had begun, the y-intercept represents the radius of the algae on the initial day.

So, when the biologist started her study, the radius of the algae was five millimeters.

Part 3)

To find the average rate of change for a nonlinear function, we find the slope between the two endpoints on the interval.

We want to find the average rate of change of f(d) from d = 4 to d = 11.

Find the endpoints:

$f(4)=5.4121...\text{ and } f(11)=6.2168...$

And find the slope between them:

$\displaystyle m=\frac{f(11)-f(4)}{11-4}=0.1149...\approx 0.11$

Since f(d) measures millimeters and d measures days, this tells us that, on average, the radius of the algae grew by about 0.11 mm per day from the 4th day to the 11th day.

5 0

2 years ago