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Serhud [2]
4 years ago
7

Please Help ASAP!!

Chemistry
1 answer:
anastassius [24]4 years ago
7 0
<h3>Answer:</h3>

#1.  2GaBr₃ + 3Na₂SO₃ → Ga₂(SO₃)₃ + 6NaBr

#2. 3SnO + 2NF₃ → 3SnF₂ + N₂O₃

<h3>Explanation:</h3>
  • Balancing chemical equations involves  putting appropriate coefficients on the products and reactants to ensure the number of atoms of each element are equal on either side of the equation.
  • Balancing chemical equations makes them obey the law of conservation of mass in chemical equations.
  • In this case; to balance the first equation, we put coefficients 2, 3, 1 and 6 on the equation.
  • That is, the balanced equation will be;

2GaBr₃ + 3Na₂SO₃ → Ga₂(SO₃)₃ + 6NaBr

  • To balance the second equation, we put coefficients 3, 2, 3 and 1 respectively.
  • Thus, the balanced chemical equation will be;

3SnO + 2NF₃ → 3SnF₂ + N₂O₃

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Answer:

See explanation.

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5 0
2 years ago
In a particular mass of kau(cn)2, there are 6.66 × 1020 atoms of gold. What is the total number of atoms in this sample?
Vinvika [58]

Total number of atoms in the sample is the sum of number of atoms of all the elements present in the sample.

Number of gold, Au atoms in KAu(CN)_2 = 6.66\times 10^{20} atoms     (given)

From the formula of compound that is KAu(CN)_2 it is clear that the number of potassium and gold are same whereas those of carbon and nitrogen are 2 times of them.

So, the number of atoms of each element is:

Number of potassium, K atoms in KAu(CN)_2 = 6.66\times 10^{20} atoms    

Number of carbon, C atoms in KAu(CN)_2 = 2\times6.66\times 10^{20} atoms = 13.32\times 10^{20}

Number of nitrogen, N atoms in KAu(CN)_2 = 2\times6.66\times 10^{20} atoms = 13.32\times 10^{20}

Total number of atoms in KAu(CN)_2 = Number of gold, Au atoms+Number of potassium, K atoms +Number of carbon, C atoms + Number of nitrogen, N atoms

Total number of atoms in KAu(CN)_2 = 6.66\times 10^{20}+6.66\times 10^{20}+13.32\times 10^{20}+13.32\times 10^{20}

Total number of atoms in KAu(CN)_2 = 39.96\times 10^{20} atoms

Hence, the total number of atoms in KAu(CN)_2 is 3.996\times 10^{21} atoms.

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3 years ago
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Work = 1.02 (1.403 - 0.055)
Work = 1.375 L-atm

Hope this answers the question. Have a nice day.
8 0
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Answer:

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