i think the answer is either A or D but im strongly going to go with D
Correct question:
if a nondisjunction occurs at anaphase I of the first meiotic division, what will the proportion of abnormal gametes (for the chromosomes involved in the nondisjunction)?
Answer:
100%
Explanation:
Nondisjunction at meiosis-I means that two homologous chromosomes of at least one homologous pair fail to separate from each other during anaphase-I. This would result in the formation of one cell with one extra chromosome and the other with one less chromosome by the end of meiosis-I. Meiosis-II in these two cells would maintain this chromosome number in the daughter cells. Therefore, out of the total four gametes formed by the end of the meiosis, two would have one extra chromosome and would be denoted as "n+1". The rest of the two gametes would have one less chromosome and would be denoted as "n-1".
Answer:
The three basic types of adaptations, based on how the genetic changes are expressed, are structural, physiological and behavioral adaptations. Most organisms have combinations of all these types
Explanation:
Let's look BB and Bb
They both have the dominant trait which means they both have the same physical appearance (phenotype) , but while BB has both dominant and Bb has one dominant and one recessive that means that although Bb has the same phenotype as BB, it has a different genotype because it has a bit different genetic makeup
<span>The structure of a paramecium that holds a "reserve copy" of all the cell's genes is the micro nucleus.
</span>The micro nucelus is one of the <span>two kinds of </span>nuclei the paramecium has. The other is the<span> large ellipsoidal </span>nucleus<span> called a macronucleus. Every paramecium must have at least one small </span>nucleus<span> called a </span>micronucleus. The micronucleus is a storage site for the germline genetic material of the organism.
