we know that
m∠SQR+x=
-------> by supplementary angles
so
m∠SQR=
The sum of the internal angles of a triangle is equal to
degrees
m∠SQR+m∠QSR+m∠SRQ=
substitute the values in the formula
m∠SQR+
+
=
m∠SQR=
degrees
<u>Find the value of x</u>
m∠SQR=
x=
-m∠SQR
x=
x=
degrees
therefore
<u>the answer is</u>
the value of x is
degrees
Answer:
Option 4 is the image of the given figure.
Step-by-step explanation:
We are given that,
The shape EFGHCD is transformed to form another shape.
From the options, we see that,
Figure 2 and 3 does not have the same vertices as that of the figure.
So, they are discarded.
Since, after transforming a figure, we get a new figure.
So, the vertices cannot have same name as that of the original figure.
So, option 1 is discarded.
Thus, we get,
Option 4 is the image of the given figure after transformation as shown below.
a LINEar function has well, the graph of a straight line, so this isn't that.
is it a relation? well, yes, because the y-value correlates with the x-value, so one depends or relates to the other.
is it a non-linear function? well, a function has to pass the <u>vertical line test</u>, meaning if we draw vertical lines they must touch the graph only once on their way down.... and in this case it seems they do, so it is non-linear clearly, and it's also a function.
When x=42 that means it is 8x6 so that means that the y = 120 becuase its 20x6
answer= y=120
Hello,
z=(1/√2-1/√2 i)^6=1/8*(1-i)^6=1/8*(√2∡-45°)^6=1/8*8∡-270°=1∡90°=i
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