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Alexeev081 [22]
3 years ago
11

Graph the line for y+1=−3/5(x−4) on the coordinate plane. Move Line Undo Redo Reset

Mathematics
1 answer:
dsp733 years ago
7 0

Answer:

The equation of  line is shown below.

Step-by-step explanation:

The equation of line is

y+1=\frac{-3}{5}(x-4)

It is the point slope form of a line, therefore the slope of the line is \frac{-3}{5} and the line passing through (4,-1).

Rewrite the above equation in slope intercept form.

y=\frac{-3}{5}x+\frac{12}{5}-1

y=\frac{-3}{5}x+\frac{12-5}{5}

y=\frac{-3}{5}x+\frac{7}{5}

The point slope form of a line is

y=mx+b

Where m is the slope and b is y-intercept.

Therefore the slope of the line is \frac{-3}{5} and the y-intercept of the line is \frac{7}{5}.

Slope is defined as

m=\frac{Rise}{Run}

Since the slope is negative, therefore the run of the line is considered on the left side. The line rise by 3 and run by 5, therefore we will add 7 in y and subtract 5 from x.

The y-intercept is (0,\frac{7}{5}).

(0-5,\frac{7}{5}+3)=(-5,\frac{22}{5})=(-5,4.4)

Therefore we have three points (4,-1), (-5,4.4) and (0,1.4). Plot the point on the coordinate plane and connect them be a straight line.

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Question 1:

For this case we have the following equation:

 5x ^ 2 = 6x + 11

We observe that the equation is a polynomial of the second degree.

Therefore, the equation has two possible solutions.

The variable of the equation for this case is x.

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Answer:

An ordered pair that is a solution of the equation y = x-4 is:

(6, 2)

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