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shtirl [24]
3 years ago
7

The population of a certain animal species you are studying decreases at a rate of 3.5% per year. Only 80 of the animals in the

habitat remain after 3 years of conducting your research. What was the initial amount of animals.
Mathematics
1 answer:
Korolek [52]3 years ago
6 0

Answer:

Therefore the initial amount of animal was 89.

Step-by-step explanation:

Given that,at rate of 3.5% per year, the population of a certain animal species decreases.

The population growth formula:

A=P(1+r)^n

A= number of population after n year.

P= initial population.

n= time in year

r= rate of growth per annum.

Here A=80, P=?, n= 3 years, r= -3.5% = -0.035[ since the rate of growth decrease]

Putting the all values,

80=P(1-0.035)^3

\Rightarrow 80= P(0.965)^3

\Rightarrow P=\frac{80}{(0.965)^3}

      ≈89.

Therefore the amount of animal at its initial stage was 89.

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Rachel has a bag of fruit that has a mass of 50 hectograms. Rachel converts this mass to centigrams. Her work is shown below.
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Answer:

She should have multiplied by 10,000

Step-by-step explanation:

Given table:

\begin{array}{| c | c |}\cline{1-2} \sf kilo & 1,000 \\\cline{1-2} \sf hecto & 100 \\\cline{1-2} \sf deka & 10 \\\cline{1-2} \sf unit & 1 \\\cline{1-2} \sf deci & 0.1 \\\cline{1-2} \sf centi & 0.01 \\\cline{1-2} \sf milli & 0.001 \\\cline{1-2}\end{array}

To find the conversion rate:

\sf \dfrac{hecto}{centi}=\dfrac{100}{0.01}=10000

Therefore, 1 hectogram = 10,000 centigrams

So when converting hectograms to centigrams, multiply the mass by 10,000.

⇒ 50 hg × 10,000 = 500,000 centigrams

Rachel's error was that she should have multiplied by 10,000.

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3 years ago
he box plot represents the number of minutes it takes for the students in a class to run a mile. What is the minimum of the data
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What is the equation of the quadratic graph with a focus of (-4,17/8) and a directrix of y=15/8
Temka [501]
So hmm notice the graph below

based on where the focus point is at, and the directrix, then, the parabola is opening upwards, meaning the squared variable is the "x"

\bf \begin{array}{llll}
(y-{{ k}})^2=4{{ p}}(x-{{ h}}) \\\\
\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}})}\\
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\qquad \textit{ focus or directrix}
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now, keep in mind, the vertex is at coordinates h,k
the vertex itself is half-way between the focus and directrix
the directrix is at y=15/8 and the focus is at y=17/8
so, half-way will then be \bf \cfrac{17}{8}-\cfrac{15}{8}=\cfrac{2}{8}\iff \cfrac{1}{4}

well, so is 1/4 between the focus point and the directrix, half of that is 1/8
so, if you move from the focus point 1/8 down, you'll get the y-coordinate for the vertex, or 1/8 up from the directrix, since the vertex is equidistant to either

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so, the x-coordinate is obviously -4, get the y-coordinate by 17/8 - 1/8   or 15/8 + 1/8

and plug your values (x-h)² = 4p(y-k)   and then solve for "y", that's the equation of the quadratic

4 0
3 years ago
The best method for obtaining a representative sample is to choose a _____ from the population of interest.
Ilya [14]

Answer:

Random sample

Step-by-step explanation:

In statistics, a sample randomly taken from an investigated population, usually known as a random sample. To avoid having bais from our response and for it to have the best chance of it being indicative of the entire population, our sample must be random. This random sample chosen must contain subjects related to the data in the population we what to obtain a result from.

3 0
3 years ago
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