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Vilka [71]
3 years ago
9

Cathy cut 2 apples into 6 slices each.She ate 9 slices.What expression matches the words?

Mathematics
2 answers:
vladimir2022 [97]3 years ago
7 0
3 apple slices are left

hope this helps!
olasank [31]3 years ago
5 0
(6×2)-9=3
6×2=12
12-9=3
3 apple slices are left
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In the figure, BD is a median. If AD=6x+10 and CD=2x+12, find the length of AC. Show your work.
Valentin [98]

Answer:

26.

Step-by-step explanation:

Given, BD is a median. As it divides the AC equally, that's why it will AD=CD. Given, AD= 6x+10 and CD= 2x+12

Now, AD=  CD

or, 6x+10=2x+12

or, 6x-2x= 12-10

or, 4x= 2

or, x= 1/2

So the value of x is 1/2. As BD divided AC equally, both AD and CD will be equal and AD+CD= AC.

So, 6x+10+2x+12= AC

or, 8x+22= AC

or, 8 X (1/2) + 22= AC

or, 4+22 = AC

or, AC= 26.

 

6 0
3 years ago
What segment is the projection of ST on QT?<br><br> UT<br> QU<br> QT
Likurg_2 [28]

Answer:

UT

Step-by-step explanation:

The projection of ST on QT is found by locating the points on QT that are nearest the endpoints S and T of the original segment. On QT, U is the point closest to S, and T is the point closest to T. Then the projection is the segment between those identified points: UT.

3 0
3 years ago
Read 2 more answers
What is the equation of the translated function?
Musya8 [376]
For this case the main function is:
 f (x) = x ^ 2
 We are going to apply the following transformations:

 Vertical translations
 Suppose that k> 0:
 To graph y = f (x) + k, move the graph of k units up.
 We have then:
 f (x) = x ^ 2 + 5

 Horizontal translations
 Suppose that h> 0
 To graph y = f (x + h), move the graph of h units to the left.
 We have then:
 f (x) = (x + 1) ^ 2 + 5

 Answer:
 
f (x) = (x + 1) ^ 2 + 5
3 0
3 years ago
Read 2 more answers
What is 12/4<br><br> what is 6/3<br><br> and what is 2/1
gregori [183]
12/4=3
6/3=2
and 2/1=2

Hope this helps!
7 0
2 years ago
Read 2 more answers
Solutions to this equation!!
otez555 [7]

Answer:

w=3/5 or w=-5

Step-by-step explanation:

5w^2+22w=15

5w^2+22w-15=0 (quadratic equation)

a=5, b=22, c=-15

w1,2 =(-b+-sqrt(b^2-4ac))/2a

w1,2 =(-22+-sqrt(22^2-4*5*(-15))/2*5

w1,2 =(-22+-sqrt(484+300))/10

w1,2=(-22+-sqrt(784))/10

w1,2=(-22+-28)/10

w1=(-22+28)/10, w2=(-22-28)/10

w1=6/10, w2=-50/10

w1=3/5, w2=-5

8 0
3 years ago
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