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neonofarm [45]
3 years ago
8

Plssss help asapppp I need it like nowwwwww

Mathematics
1 answer:
bulgar [2K]3 years ago
4 0

Answer: d

Step-by-step explanation:

use the formula a^2+b^2=c^2

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Leo has $4.80 in dimes a d quarters he has 6 more dimes than quarters how many quarters does he have
Kryger [21]

Answer:

Step-by-step explanation:

he has 4.80 in dimes and quarters....dimes (d) are worth 0.10 and quarters (q) are worth 0.25

0.10d + 0.25q = 4.80

he has 6 more dimes then quarters

d = q + 6

====================

d = q + 6...so we sub q + 6 in for d, back into the other equation

0.10(q + 6) + 0.25q = 4.80

0.10q + 0.60 + 0.25q = 4.80

0.35q = 4.80 - 0.60

0.35q = 4.20

q = 4.20 / 0.35

q = 12 <====== there is 12 quarters

d = q + 6

d = 12 + 6

d = 18 <===== there is 18 dimes

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14+2(14)=42. this is the answer
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ritvik tosses a ball from where he stands on a balcony to his friend on the ground. the height, in feet, of the ball can be repr
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3 years ago
A random sample of n observations is selected from a normal population to test the null hypothesis that muμequals=10. Specify th
brilliants [131]

Answer:

Step-by-step explanation:

a) H0: μ = 10

Ha: μ ≠ 10

This is a two tailed test

n = 13

Since α = 0.01, the critical value is determined from the t distribution table. Recall that this is a two tailed test. Therefore, we would find the critical value corresponding to 1 - α/2 and reject the null hypothesis if the absolute value of the test statistic is greater than the value of t 1 - α/2 from the table.

1 - α/2 = 1 - 0.01/2 = 1 - 0.005 = 0.995

The critical value is 3.012

The rejection region is area > 3.012

b) Ha: μ > 10

This is a right tailed test

n = 23

α = 0.1

We would reject the null hypothesis if the test statistic is greater than the table value of 1 - α

1 - α = 1 - 0.1 = 0.9

The critical value is 1.319

The rejection region is area > 1.319

c) Ha: μ > 10

This is a right tailed test

n = 99

α = 0.05

We would reject the null hypothesis if the test statistic is greater than the table value of 1 - α

1 - α = 1 - 0.05 = 0.95

The critical value is 1.66

The rejection region is area > 1.66

d) Ha: μ < 10

This is a left tailed test

n = 11

α = 0.1

We would reject the null hypothesis if the test statistic is lesser than the table value of 1 - α

1 - α = 1 - 0.1 = 0.9

The critical value is 1.363

The rejection region is area < 1.363

e) H0: μ = 10

Ha: μ ≠ 10

This is a two tailed test

n = 20

Since α = 0.05, we would find the critical value corresponding to 1 - α/2 and reject the null hypothesis if the absolute value of the test statistic is greater than the value of t 1 - α/2 from the table.

1 - α/2 = 1 - 0.05/2 = 1 - 0.025 = 0.975

The critical value is 2.086

The rejection region is area > 2.086

f) Ha: μ < 10

This is a left tailed test

n = 77

α = 0.01

We would reject the null hypothesis if the test statistic is lesser than the table value of 1 - α

1 - α = 1 - 0.01 = 0.99

The critical value is 2.376

The rejection region is area < 2.376

7 0
3 years ago
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