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lutik1710 [3]
3 years ago
9

Which expression can be simplified as 718? ? • (m2) (nojo o o (no) 6

Mathematics
2 answers:
velikii [3]3 years ago
6 0
The answer is the 4th one
BabaBlast [244]3 years ago
3 0
The answer is (n^-3)^6
The fourth option
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Find the surface area. Round your answers to the nearest hundredths if necessary.
cupoosta [38]
Area of triangle = (base x height)/2
There are all together 4 triangles and 1 square. 
Therefore, surface area = area of square + 4 x area of triangle 

height = 5.8 in, base = 6 in. area of square = 6x6 = 36 in^2.

area of 1 triangle = (5.8x6)/2 
area of 4 triangles = 2x5.8x6 = 69.6 in^2

surface area = 69.6 + 36 = 105.6 in^2
8 0
3 years ago
Same side exterior angles if m<1=4x+15 and m<8=3x+11, solve for the value of x
ella [17]

Answer:

x = 22

Step-by-step explanation:

same- side exterior angles are supplementary, thus

4x + 15 + 3x + 11 = 180, that is

7x + 26 = 180 ( subtract 26 from both sides )

7x = 154 ( divide both sides by 7 )

x = 22

7 0
4 years ago
You divided 2/3 of a gallon of paint equally among 4 containers. How much paint is in each container.
Hunter-Best [27]

Answer:

1/6 a gallon of paint is in each container

Step-by-step explanation:

2/3 * 1/4 = 2/12

2/12 = 1/6

3 0
2 years ago
A crowbar 29 in. long is pivoted 6 in. from the end. What force must be applied at the long end in order to lift a 700 Ib object
Alla [95]

A force of 182.6 lb should be applied to lift 700 lb object.

<h3>How to calculate the force?</h3>

Let the force required to lift be F

Total length = 29 in.

Distance of short end from pivot =  in.

Distance from long end = 29-6 = 23 in.

Now Equating moments

F × 23 = 700x6

23F = 4200

F = 4200/23

= 182.6 lb

A force of 182.6 lb should be applied to lift 700 lb object.

Learn more about force on:

brainly.com/question/12970081

#SPJ1

6 0
2 years ago
Check whether the function yequalsStartFraction cosine 2 x Over x EndFraction is a solution of x y prime plus yequalsnegative 2
Jobisdone [24]

The question is:

Check whether the function:

y = [cos(2x)]/x

is a solution of

xy' + y = -2sin(2x)

with the initial condition y(π/4) = 0

Answer:

To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.

Let us do that.

y = [cos(2x)]/x

y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]

Now,

xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x

= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)

= -2sin(2x)

Which is the right hand side of the differential equation.

Hence, y is a solution to the differential equation.

6 0
4 years ago
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