9.05 as a improper fraction
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A motorist drove 150 miles in the morning and;
50 miles in the afternoon
His average rate in the morning was twice his average rate in the afternoon
He spent 5hrs driving
Let the times spent driving in the morning be x
Average speed = Distance ÷ time
= 2(
)
Cross multiplying gives;
750 - 150x = 100x
250x = 750 , x =3
Average speed in the morning is 150/3 = 50miles/hr
Average speed in the afternoon = 50/(5-3) = 25miles/hr