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3 years ago

Help meeeeeeeeeeeeeeeeeeeeeee !!!!!

Mathematics

1 answer:

stiv31 [10]3 years ago

6 0

Answer:

i think it is the 2nd one and the 5th one.

Step-by-step explanation:

hope this helped!

p.s it would be cool if you gave me brainliest

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Simplify the expression 63 + 5(4-2)

Natalka [10]

Answer:

63 + 10

Step-by-step explanation:

when you do parenthesis and the number is next to another one with no symbol you multiply so 4-2 = 2 2 x 5 = 10 giving you 63 + 10

6 0

2 years ago

Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)

USPshnik [31]

First, expand the terms inside the bracket you will get

$(( \tan {}^{2} (x) + 2 \tan(x) \sin(x) + \sin {}^{2} (x) - ( \tan {}^{2} (x) - 2 \tan(x) + \sin {}^{2} (x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$( 4 \tan(x) \sin(x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) \sin {}^{2} (x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) (1 - \cos {}^{2} (x) ) = 16 (\tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan {}^{2} (x) - \frac{ \sin {}^{2} (x) \cos {}^{2} ( {x}^{} ) }{ \cos {}^{2} (x) }$

$16( \tan {}^{2} (x) - \sin {}^{2} (x) ) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

5 0

2 years ago

Suppose that z-scores come from a standard normal distribution. Use the Normal Probability Applet (Links to an external site.) t

Natalka [10]

Answer:

0.683

Step-by-step explanation:

We have to find P(-1<z<1).

For this purpose, we use normal distribution area table

P(-1<z<1)=P(-1<z<0)+(0<z<1)

Using normal area table and looking the value corresponds to 1.0, we get

P(-1<z<1)=0.3413+0.3413

P(-1<z<1)=0.6826

Rounding the answer to three decimal places

P(-1<z<1)=0.683

So, 68.3% of the z-scores will be between -1 an 1.

4 0

3 years ago

Suppose a parabola has vertex (6,5) and also passes through the point (7,7). Write the equation of the parabola in vertex form.

jek_recluse [69]

Answer:

Choice B: $y = 2\, (x - 6)^{2} + 5$ .

Step-by-step explanation:

For a parabola with vertex $(h,\, k)$ , the vertex form equation of that parabola in would be:

$\text{$y = a\, (x - h)^{2} + k$ for some constant $a$}$ .

In this question, the vertex is $(6,\, 5)$ , such that $h = 6$ and $k = 5$ . There would exist a constant $a$ such that the equation of this parabola would be:

$y = a\, (x - 6)^{2} + 5$ .

The next step is to find the value of the constant $a$ .

Given that this parabola includes the point $(7,\, 7)$ , $x = 7$ and $y = 7$ would need to satisfy the equation of this parabola, $y = a\, (x - 6)^{2} + 5$ .