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2 years ago

Sorry about the rainbow stuff but what’s the answer

Mathematics

1 answer:

serious [3.7K]2 years ago

5 0

Answer:

16 strips

Step-by-step explanation:

37.75/2.25=16.8...

Since you can't cut a fraction of what they need, 16 should be the answer

hope this helps :)

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Which relationship describes angles 1 and 2?

malfutka [58]

Answer:

vertical angles

Step-by-step explanation:

When two lines intersect at a single point, they form 4 angles. Two angles that are not adjacent are vertical angles. With an intersection of two lines art a single point, there are two pairs of vertical angles. Angles 1 and 2 are vertical angles.

5 0

3 years ago

Read 2 more answers

I don’t know how to do this I am very bad at math

maw [93]

Answer:

Surface area= 7.5

Step-by-step explanation:

The area of a triangle is b*h/2. so if you fill in the numbers your equation would be 5*3/2. 5*3=15 and 15/2=7.5

hope this helps!!

5 0

3 years ago

Complete the proof for me please, I need help

Naya [18.7K]

Answer:

See explanation for answers

Step-by-step explanation:

Reason 1) Given from the problem statement(because it says that B is the midpoint of AC)

Reason 2) Because B is the midpoint of AC

Reason 3) Given frome the problem statement(because it says that AB/cong CD)

Reason 4) Because two lines congruent to each other have the same length

Reason 5(You didn't explain well)) BC=AB=CD, so BC=CD(Specific reason: Transitivity of equality)

And we're done!

4 0

3 years ago

Use the Chain Rule (Calculus 2)

atroni [7]

1. By the chain rule,

$\dfrac{\mathrm dz}{\mathrm dt}=\dfrac{\partial z}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial z}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}$

I'm going to switch up the notation to save space, so for example, $z_x$ is shorthand for $\frac{\partial z}{\partial x}$ .

$z_t=z_xx_t+z_yy_t$

We have

$x=e^{-t}\implies x_t=-e^{-t}$

$y=e^t\implies y_t=e^t$

$z=\tan(xy)\implies\begin{cases}z_x=y\sec^2(xy)=e^t\sec^2(1)\\z_y=x\sec^2(xy)=e^{-t}\sec^2(1)\end{cases}$

$\implies z_t=e^t\sec^2(1)(-e^{-t})+e^{-t}\sec^2(1)e^t=0$

Similarly,

$w_t=w_xx_t+w_yy_t+w_zz_t$

where

$x=\cosh^2t\implies x_t=2\cosh t\sinh t$

$y=\sinh^2t\implies y_t=2\cosh t\sinh t$

$z=t\implies z_t=1$

To capture all the partial derivatives of $w$ , compute its gradient:

$\nabla w=\langle w_x,w_y,w_z\rangle=\dfrac{\langle1,-1,1\rangle}{\sqrt{1-(x-y+z)^2}}}=\dfrac{\langle1,-1,1\rangle}{\sqrt{-2t-t^2}}$

$\implies w_t=\dfrac1{\sqrt{-2t-t^2}}$

2. The problem is asking for $\frac{\partial z}{\partial x}$ and $\frac{\partial z}{\partial y}$ . But $z$ is already a function of $x,y$ , so the chain rule isn't needed here. I suspect it's supposed to say "find $\frac{\partial z}{\partial s}$ and $\frac{\partial z}{\partial t}$ " instead.